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VikaD [51]
3 years ago
14

29.06=? tenth + 6 hundredth

Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0

Answer:

0

Step-by-step explanation:

After the decimal point is the tenths place, and after the tenths place is the hundredths place.

After the decimal point is the number 0, which is at the tenths place. After the tenths place is 6, which is at the hundredths place.

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Mr. Walker asked his students to use the associative property to find an expression that is equivalent to (13 + 15 + 20) + (20 +
ozzi
HERES THE ANSWER AND EXPLINATION

⇒Associative property of Addition is applied for three real numbers.For, any three real numbers, A, B and C
≡A+B+C=A+(B+C)=(A+B)+C=(A+C)+B→→→Associative Property of Addition
that is , we can add any two numbers first and then the third number with them.
⇒Also, Commutative Property of Addition of two numbers says that for any two numbers , A and B
≡A+B=B+A
We have to find equivalent expression using Associative Property of the sum of set of three numbers
→→(13+15+20)+(20+47+18)
Answer Written by Jerry
→(20+13+15)+(20+47+18)
Answer Written by Layla
→(20+47+18)+(13+15+20)
The Expression Written by Keith and Melinda is Incorrect,because they haven't used the bracket Properly, as associative property says that you can add any two numbers first and then the third number among three numbers.
→→Number of Students who has applied the Associative property Correctly
Option B ⇒Two(Jerry, Layla)
8 0
3 years ago
Find the mass of the triangle with vertices (1; 0; 0), (0; 2; 0), (0; 1; 1) if the density function is given by (x; y; z)
Luda [366]

Answer:

=\frac{17}{3}

Step-by-step explanation:

Density of a function is \rho(x,y)=x^{2} +y^{2}

I have drawn the right angle triangle for visualization

equation for the line passing through (1,0) and (0,4) is

\frac{y}{4} =\frac{x-1}{-1}

y=4-4x

=$$\int_{0}^1\int_{0}^{4-4x} (x^{2}+y^{2})dydx$$

=$\int_{0}^{1}(x^{2}+\frac{y^{3} }{3})dx$  

=$\int_{0}^{1}(x^{2}(4-4x)+\frac{1}{3}(4-4x)^{3} )dx$

=$\int_{0}^{1}(\frac{-76}{3}x^{3} +68x^{2}-64x^{}+\frac{64}{3}  )dx$

==(\frac{-76}{3} \frac{x^{4} }{4})+\frac{68}{3}x^{3}-32x^{2}+\frac{64}{3}x^{})  

=\frac{17}{3}

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3 years ago
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HACTEHA [7]
-5/6=(8,4)(x,y)
-5/6=y-4/x-8
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