The sum of 5 consecutive integers is 110<span>.
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Answer:
Step-by-step explanation:
1.52063492063
Answer:
1/2
Step-by-step explanation:
(1/16)^x
Let x = 1/4
(1/16)^ 1/4
Rewriting 16 as 2^4
(1/2^4)^ 1/4
We know that 1 / a^b = a^-b
(2 ^ -4)^ 1/4
We know that a^b^c = a^(b*c)
2^(-4*1/4)
2^-1
We know that a^-b = 1/ a^b
2^-1 = 1/2^1 = 1/2
