Answer:
y = 3(x -2)² -5
Step-by-step explanation:
It looks like you want to write the standard-form quadratic ...
y = 3x² -12x +7
in vertex form.
The process is similar to that of "completing the square."
<h3>Steps</h3>
<u>Factor out the leading coefficient</u>
Do this for the variable terms only.
y = 3(x² -4x) +7
<u>Identify the x-term coefficient</u>
The x-term coefficient (inside parentheses) divided by 2 is the opposite of the x-coordinate of the vertex. It is the constant term in the squared binomial of the vertex form. Square this value.
x coefficient: -4
binomial constant: -4/2 = -2
square of this: (-2)² = 4
<u>Add this inside parentheses</u>
To keep the overall equation unchanged, you must also subtract an equal amount outside parentheses.
y = 3(x² -4x +4) +7 -3(4)
<u>Simplify to vertex form</u>
Write the trinomial in parentheses as a square, and simplify the y-coordinate of the vertex.
y = 3(x -2)² -5
The answer is 20.4 you just multiply 1.70 by 12
A*2 + b* = c*2
(9)*2 + (8)*2
81+64= 145
145=c*2
12.04=c
Answer:Hence, x = 5, y = 0 is the required solution.
Step-by-step explanation:
