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2 years ago

Please help due in an hour!!!

Mathematics

2 answers:

lions [1.4K]2 years ago

3 0

Answer:

The answer is C

Step-by-step explanation:

sweet-ann [11.9K]2 years ago

3 0

Which grade? --------_______-------

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Please help:<br> In PQR, sin P=64, sin R=35, and r=21. Find the length of p.

son4ous [18]

Answer:

32.9 units

Step-by-step explanation:

p/sinP = r/sinR

p = sinP × r/sinR

p = sin(64) × 21/sin(35)

p = 32.9069916

5 0

2 years ago

Plz solve anyone I having trouble answering this someone respond fast

Ipatiy [6.2K]

Answer:

55 6/9

Step-by-step explanation:

3 0

3 years ago

Prove : (sec θ - tan θ )^2 = 1 - sin θ /1+sin θ

labwork [276]

$(sec x - tan x)^2 \\ \\ = sec^2x - 2 sec x tan x + tan^2 x \\ \\ =(1+tan^2 x) - 2 sec x tan x +tan^2 x \\ \\ =1 - 2 sec x tan x + 2 tan^2 x \\ \\ = 1 - 2tan x(sec x - tan x) \\ \\ =1 - \frac{2 sin x}{cos x} (\frac{1-sin x}{cos x}) \\ \\ = 1 - \frac{2 sin x (1-sin x)}{cos^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{1-sin^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{(1-sin x)(1+sin x)} \\ \\ =1-\frac{2 sin x}{1+sin x}$

3 0

2 years ago

Which statement is true about the two triangles?

mote1985 [20]

C is the correct answer

4 0

3 years ago

Plz help ASAP plz!!!

zysi [14]

Answer:

tan38 = 0.31

cos47 = -0.99

sin77 = 0.99

Step-by-step explanation:

There are several free online calculators that can help you do this! I recommend Desmos!

7 0

3 years ago

Please help due in an hour!!!​

Please help due in an hour!!!