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2 years ago

23.21

1 answer:

4 0

The equation that represents the relationship between the number of liters, x, and the number of liquid pints, y is y = 2.11x

<h3>How to determine the equation?</h3>

The attached table of values represents the missing piece in the question.

Start by calculating the rate of change using:

m = (y2 - y1)/(x2 - x1)

This gives

m = (14.77 - 10.55)/(7- 5)

Evaluate

m = 2.11

The equation is then calculated using:

y = m(x - x1) + y1

This gives

y = 2.11(x - 5) + 10.55

Evaluate

y = 2.11x - 10.55 + 10.55

y = 2.11x

Hence, the equation that represents the relationship between the number of liters, x, and the number of liquid pints, y is y = 2.11x

Read more about linear equations at:

brainly.com/question/14323743

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Solve <br> 3c-5=2c+5<br> please naswer fast and I will give you 5 stars

Masja [62]

Answer:

Step-by-step explanation:

3c - 5 =2c +5

3c - 2c =5 +5

c=10

4 0

3 years ago

Which choice is the equation of a line that passes through (9, -3) and is parallel to the line represented by this equation? y=5

miskamm [114]

Answer:

$y+3=\frac{5}{3}(x-9)$ or $y=\frac{5}{3}x-18$

Step-by-step explanation:

step 1

Find the slope of the line parallel to the given line

we know that

If two lines are parallel, then their slopes are the same

we have

$y=\frac{5}{3}x-4$

therefore

The slope m of the line parallel to the given line is

$m=\frac{5}{3}$

step 2

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{5}{3}$

$point\ (9,-3)$

substitute

$y+3=\frac{5}{3}(x-9)$ ----> equation of the line in point slope form

step 3

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$y+3=\frac{5}{3}(x-9)$

Isolate the variable y

$y+3=\frac{5}{3}x-15$

$y=\frac{5}{3}x-15-3$

$y=\frac{5}{3}x-18$

7 0

3 years ago

Help me please I beg

valentina_108 [34]

Answer:

$8,500

Step-by-step explanation:

Interest = 5000 x 5 x 0.14

= 1000 x 0.14 x 25

= 140 x 25

= 3500

5000 + 3500 = 8500

8 0

2 years ago

Write down the bearing of: (a) Henly from Dinder (b) Dinder from Weare (c) Weare from Dinder (d) Weare from Henly (e) Dinder fro

Neko [114]

The bearing of the individuals from each other are as indicated below;

S45°E
N25°E
S65°E
S15°E
N45°E
N75°E

<h3>What is bearing of Henley from Dinder?</h3>

It follows from the task content that the bearing of the individuals from each other are expected to be determined.

a) For Henley from Dinder; it follows from observation that Henley is; S45°E of Dinder's position.

b) For Dinder from Weare; it follows from observation that Dinder is; N25°E of Weare's position.

c) For Weare from Dinder; it follows from observation that Weare is; S65°E of Dinder's position.

d) For Weare from Henly; it follows from observation that Weare is; S15°E of Dinder's position.

e) For Dinder from Henly; it follows from observation that Dinder is; N45°E of Henly's position.

f) For Henly from Weare; it follows from observation that Henly is; N75°E of Weare's position.