n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
Triangle & semicircle
Step-by-step explanation:
Answer:
Step-by-step explanation:
f(x)=2(x+4)(x-1)
=(2x+8)(x-1)
<h3>=2x²-2x+8x-8</h3>
=2x²+6x-8
Answer:
$2983.65
Step-by-step explanation:
A = $2000
=
Answer: 2/3^3
Step-by-step explanation:
To find the volume of a box, you use the formula, Lenth*Width*Height=Volume
The Lenth is 3 1/2. The width is 1 1/3 and the height is 2/14
Plug the values in formula
3 1/2*1 1/3*2/14
Covert the mixed numbers into imporper fractions so it is easier to solve
3 1/2=7/2
1 1/3=4/3
7/2*4/3*2/14
Reduce 2/14
2/14=1/7
7/2*4/3*1/7=7*4*1/(2*3*7)=28/42
Reduce 28/42=14/21=2/3
2/3 ft^3
