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3 years ago

Thank you! Please do both

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

Answer:

my 12 inch pito that pito good

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What did I do wrong so I don’t do it again on the test

denpristay [2]

Answer:

nothing

Step-by-step explanation:

all of them seem to be right. if you need practice work on alternate interior angles, exterior angles

8 0

2 years ago

3n+4 first the 7 terms

kiruha [24]

Answer:

4, 7, 10, 13, 16, 19, 22

Step-by-step explanation:

Not sure if there is more to this question but here is what I assume:

We want to find the first 7 terms of this equation given 3n+4

Assuming we are starting at 0 we plug 0 in for n.

3(0) + 4 → 4

So our first answer is 4

We continue by pugging in the next numbers after that to get to the first 7 terms

3(1) + 4 → 7

3(2) + 4 → 10

3(3) + 4 → 13

3(4) + 4 → 16

3(5) + 4 → 19

3(6) + 4 → 22

5 0

3 years ago

The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin

hoa [83]

Answer:

$\frac{dI}{dt}=-0.00016 A/s$

Step-by-step explanation:

We are given that

By ohm's law

$V=IR$

R=389 ohm

I=0.03 A

$\frac{dV}{dt}=-0.06V/s$

$\frac{dR}{dt}=0.07ohm/s$

We have to find rate of change of current I means $\frac{dI}{dt}$

Differentiate the equation w.r.t t

$\frac{dV}{dt}=\frac{dI}{dt}R+I\frac{dR}{dt}$

Substitute the values then we get

$-0.06=\frac{dI}{dt}\times 389+0.03\times 0.07$

$-0.06=389\frac{dI}{dt}+0.0021$

$-0.06-0.0021=389\frac{dI}{dt}$

$-0.0621=389\frac{dI}{dt}$

$\frac{dI}{dt}=\frac{-0.0621}{389}=-0.000160 A/s$

Hence, the current I is changing at the rate=-0.00016A/s

4 0

4 years ago

<img src="https://tex.z-dn.net/?f=tan20%2B4sin20%3D%5Csqrt%7B3%7D" id="TexFormula1" title="tan20+4sin20=\sqrt{3}" alt="tan20+4si

zepelin [54]

tan( 20 ) + 4 Sin( 20 ) =

( Sin( 20 ) / Cos( 20 ) ) + 4 Sin( 20 ) =

Sin( 20 ) + 4 Sin( 20 ).Cos( 20 ) / Cos( 20 ) =

Sin( 20 ) + 2 × 2 Sin(20).Cos(20)/ Cos(20) =

Sin( 20 ) + 2 × Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Cos( 50 ) / Cos ( 20 ) =

Sin( 20 ) + 2Cos( 20 + 30 ) / Cos( 20 ) =

________________________________

2 × Cos( 30 + 20 ) =

2 × [ Cos(30).Cos(20) - Sin(30).Sin(20) ] =

2 × [ √3/2 × Cos(20) - 1/2 × Sin(20) ] =

√3 Cos(20) - Sin(20)

_________________________________

Sin( 20 ) + 2Cos ( 20 + 30 ) / Cos( 20 ) =

Sin( 20 ) + √3 Cos(20) - Sin(20) / Cos(20) =

Sin(20) - Sin(20) + √3 Cos(20) / Cos(20) =

0 + √3 Cos(20) / Cos(20) =

√3 Cos(20) / Cos(20) =

Cos(20) simplifies from the numerator and denominator of fraction

√3 × 1 / 1 =

√3

And we're done ....

5 0

3 years ago

Which of the following best describes the equation below?

WARRIOR [948]

Answer:

Where is the question?????

4 0

3 years ago