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Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

Answer:

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Amanda exercised for 10 minutes every day in the first week, 20 minutes in the second week, 30 minutes in the third week, and 40

Misha Larkins [42]

Amanda Billy
1st week 10 5
2nd week 20 10
3rd week 30 20
4th week 40 40
<span>
A) Amanda's method is linear because the number of minutes increased by an equal number every week.</span>
common difference is 10.
1st week 0 + 10 = 10
2nd week 10 + 10 = 20
3rd week 20 + 10 = 30
4th week 30 + 10 = 40

Billy's method is exponential:
5(2)^x

1st week 5(2⁰) = 5(1) = 5
2nd week 5(2¹) = 5(2) = 10
3rd week 5(2²) = 5(4) = 20
4th week 5(2³) = 5(8) = 40

8 0

3 years ago

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30 \div \frac{1}{3} 30÷ 3 1

ioda

Answer:

Step-by-step explanation:

$30 \div \frac{1}{3} \\\\\mathrm{Convert\:element\:to\:fraction}:\quad \:30=\frac{30}{1}\\=\frac{30}{1}\div \frac{1}{3}\\\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}\\=\frac{30}{1}\times \frac{3}{1}\\\\\mathrm{Apply\:rule}\:\frac{a}{1}=a\\=30\times \:3\\\\=90$

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3 years ago

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The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$