All categories

2 years ago

(5 pts) Calculating Heat from Thermochemical Equations

Chemistry

1 answer:

Vadim26 [7]2 years ago

8 0

The heat that is released by the combustion of 3.5 moles of methane is 3115 kJ/mol.

<h3>What is a thermochemical equation?</h3>

A thermochemical equation is a reaction equation that incorporates the amount of heat lost/gained.

In this case, the reaction equation is; CH4 + O2 ----->CO2 + 2H2O dH = -890 kJ/mol

If 1 mole of methane releases 890 kJ/mol

3.5 moles of methane will release 3.5 moles * 890 kJ/mol/1 mole

= 3115 kJ/mol

Learn more about combustion reaction:brainly.com/question/12172040?

#SPJ1

You might be interested in

How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos

Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of $H_3PO_4$ = 54.219 g

Number of atoms of $Mg$ = $7.179\times 10^{23}$

Molar mass of $H_3PO_4$ = 98 g/mol

First we have to calculate the moles of $H_3PO_4$ and $Mg$ .

$\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}$

$\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol$

and,

$\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2$

From the balanced reaction we conclude that

As, 3 mole of $Mg$ react with 2 mole of $H_3PO_4$

So, 0.553 moles of $Mg$ react with $\frac{2}{3}\times 0.553=0.369$ moles of $H_3PO_4$

From this we conclude that, $H_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $Mg$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $H_2$

From the reaction, we conclude that

As, 3 mole of $Mg$ react to give 3 mole of $H_2$

So, 0.553 mole of $Mg$ react to give 0.553 mole of $H_2$

Now we have to calculate the volume of $H_2$ gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies $0.553\times 22.4=12.4L$ volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

4 0

3 years ago

If 3.00 g of aluminum hydroxide reacts with 1.40 g of sulfuric acid, what is the mass of water produced?

Leokris [45]

The Law of Conservation of Mass states that matter is not created nor destroyed.

Based on this, we can use some addition to find the answer.

3.00 + 1.40 = 4.40 g

Hope this helps :)

4 0

3 years ago

Identify the element: 6 energy level, metallic, 82 election

Lady bird [3.3K]

<u>Answer</u>:-

Name of element = Lead

Symbol ♾ of Lead = Pb

Atomic no. = 82

Atomic mass = 207.2 amu

No. of protons = 82

No. of electrons = 82

Yes, lead(Pb) is a metallic element and certainly it has 6 electron shells which means 6 energy level.

If you find anything unclear you can ask me...

6 0

3 years ago

A patient needs to be given exactly 1000 ml of a 5.0% (w/v) intravenous glucose solution. the stock solution is 55% (w/v). how m

LiRa [457]

The patient needs 1000 ml of 5% (w/v) glucose solution
i.e 1000 ml x 5 g/ 100 ml
where the stock solution is 55% (w/v) = 55 g / 100 ml
So, 1000 ml x 5 g / 100 ml = V (ml) x 55 g / 100 ml
V = 1000 x (5 / 100) / (55 / 100) = 5000 / 55 = 90.9 ml
∴ the patient needs 90.9 ml of 55% (w/v) glucose solution

6 0

4 years ago

The oxidizing agent in 2H2S + 3O2 → 2SO2 + 2H2O is

Dovator [93]

Hello, Ginamuhs2!

The oxidizing agent in 2H2S + 3O2 → 2SO2 + 2H2O is the oxygen.

I hope this helps;)

8 0

3 years ago