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maksim [4K]
4 years ago
13

What percentage of pure alcohol is in a shot of 100 proof liquor?

Chemistry
1 answer:
Alex_Xolod [135]4 years ago
7 0
<span>First of all, an ounce of hard liquor (gin, vodka, rum, whiskey, or scotch) contains 64 calories for 80 proof varieties, and 80 calories for those that are100 proof. The proof refers to the percentage of alcohol in the liquor (80 proof is 40 percent alcohol; 100 proof is 50 percent alcohol)</span>
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Which of the following elements is a representative element?
Lubov Fominskaja [6]
B. aluminum is the representative element. :)
5 0
3 years ago
Please use the values in the resources listed below instead of the textbook values. Under certain conditions the decomposition o
Alex787 [66]

Answer:

The rate equation for this reaction:

R=k[NH_3]^0

Explanation:

Decomposition of ammonia:

2NH_3\rightarrow N_2+3H_2

Rate law of the can be written as;

R=k[NH_3]^x

1) Rate of the reaction , when [NH_3]=2.0\times 10^{-3} M

1.5\times 10^{-6} M/s=k[2.0\times 10^{-3} M]^x..[1]

2) Rate of the reaction , when [NH_3]=4.0\times 10^{-3} M

1.5\times 10^{-6} M/s=k[4.0\times 10^{-3} M]^x..[2]

[1] ÷ [2]

\frac{1.5\times 10^{-6}M/s}{1.5\times 10^{-6}M/s}=\frac{k[2.0\times 10^{-3}M]^x}{k[4.0\times 10^{-3}M]^x}

On solving for x , we get ;

x = 0

The rate equation for this reaction:

R=k[NH_3]^0

4 0
3 years ago
What is the angle between the carbon-sulfur bonds in the carbon disulfide ( cs2 ) molecule?
Bingel [31]

Answer:

180º

Explanation:

Carbon has 4 valence electrons and to complete the octet requires 4 more , so it will share with the oxigen atoms 4 more, forming a single and a pi bond similar to CO2

Since the carbon does not have lone pairs, the geometry around this central atom will be linear and the angle will be 180 ,   S = C = S

7 0
3 years ago
13 moles of water to molecules
FromTheMoon [43]
I’m confused what are you asking exactly?
6 0
3 years ago
At 25∘C, the decomposition of dinitrogen pentoxide, N2O5(g), into NO2(g) and O2(g) follows first-order kinetics with k=3.4×10−5
Annette [7]

Answer:

4600s

Explanation:

2N_{2}O_{5}(g) - - -> 4NO_{2}(g) +O_{2}

For a first order reaction the rate of reaction just depends on the concentration of one specie [B] and it’s expressed as:

-\frac{d[B]}{dt}=k[B] - - -  -\frac{d[B]}{[B]}=k*dt

If we have an ideal gas in an isothermal (T=constant) and isocoric (v=constant) process.

PV=nRT we can say that P = n so we can express the reaction order as a function of the Partial pressure of one component.  

-\frac{d[P(B)]}{P(B)}=k*dt  

-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=k*dt

Integrating we get:

\int\limits^p \,-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=\int\limits^ t k*dt

-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])=k(t_{2}-t_{1})

Clearing for t2:

\frac{-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])}{k}+t_{1}=t_{2}

ln[P(N_{2}O_{5})]=ln(650)=6.4769

ln[P(N_{2}O_{5})_{o}]=ln(760)=6.6333

t_{2}=\frac{-(6.4769-6.6333)}{3.4*10^{-5}}+0= 4598.414s

4 0
3 years ago
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