Answer:
Atom
Explanation:
The smallest unit which maintains an element's properties is an atom.
density = mass /volume
1)mass of rock = 26.0 gram
2)volume of rock = volume of water it has displaced= 25.3-13.12 = 12.18
put the value of mass and volume in first equation and get the density value
Answer:

Explanation:
Hello.
In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

Best regards.
The answer is A hope this help