Answer:
(a) true
(b) true
(c) false; {y = x, t < 1; y = 2x, t ≥ 1}
(d) false; y = 200x for .005 < |x| < 1
Step-by-step explanation:
(a) "s(t) is periodic with period T" means s(t) = s(t+nT) for any integer n. Since values of n may be of the form n = 2m for any integer m, then this also means ...
s(t) = s(t +2mt) = s(t +m(2T)) . . . for any integer m
This equation matches the form of a function periodic with period 2T.
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(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:
s(a) +s(b) = s(a+b) . . . . definition of linear function
Then if a=b, you have
2s(a) = s(2a)
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(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.
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(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.
I think the answer is D I'm not sure though
The answer is true because they aren't related varables
Answer:
Step-by-step explanation:
Analysis:
2(5x+4)=17
10x+8=17,
- Subtract 8 from both sides to isolate x
10x=9
- Divide both sides by 10 to isolate x
x=9/10 (ans)
Answer:
Part A: See detail below.
Part B: Company B charges less than company A for 8 windows.
Part C: The saving using company B for 6 windows is $3.
Step-by-step explanation:
Part A:
Company A: (total charges) = ($6)x(N number of windows)+($12)
Company B: (total charges) = ($5)x(N number of windows)+($15)
Part B:
Company A for 8 windows: 6*8+12=$60
Company B for 8 windows: 5*8+15=$55
Part C:
(Saving) = (6*6+12)-(6*5+15)=48-45= $3
