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const2013 [10]
2 years ago
8

A man bought a car for Gh55,000.00 and sold it for Gh65,000.00. Find the percentage gain.

Mathematics
1 answer:
IgorLugansk [536]2 years ago
5 0

Answer:

18.18%

Step-by-step explanation:

(65000-55000)/55000×100

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a quart of paint covers 80 square feet. how many quarts should you buy to paint the ramp with two coats(Assume you will not pain
Evgesh-ka [11]
The answer would be 160 because 80+80=160
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Raj wants to get a tropical fish tank. The pet store owner tells him that he needs a tank that has a total volume equal to 80 ou
Andrew [12]

Answer:put the pictures of the tanks

Step-by-step explanation:

6 0
3 years ago
Please help me- pt. 4
nignag [31]

11/30 bags of mulch is needed.

<u>Step-by-step explanation:</u>

We have to find the number of bags of mulch.

7 (1/2) sq. yards need 2(3/4) bags of mulch.

So one sq. yd need 2(3/4) / 7(1/2)

We have to change the mixed fraction into improper fraction and then dividing them we will get the answer.

2(3/4) = ((2×4)+ 3)/4 = (8+ 3)/4 = 11/4

7(1/2) = ((7×2)+1)/2 = (14+1)/2 = 15/2

11/4 ÷ 15/2

It change into multiplication as,

11/4 × 2/15 = 11/30 bags of mulch is needed.

<u></u>

6 0
3 years ago
Roman completed the square to solve the equation 0=−x2+6x−15 0 = − x 2 + 6 x − 15 as follows. Step 1: x2−6x+15=0 x 2 − 6 x + 15
aleksandr82 [10.1K]

Answer:

yes

Step-by-step explanation:

at step 6, his meant to add 3 to both side not subtract

and at step 7, it's meant to be i√6 not i6

hope this helps:)

5 0
2 years ago
David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the
tamaranim1 [39]

Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

  • A(t) is the amount of money after t years.  
  • P is the principal(the initial sum of money).  
  • r is the interest rate(as a decimal value).  
  • n is the number of times that interest is compounded per year.  
  • t is the time in years for which the money is invested or borrowed.

In this problem:

  • The APR is of 2.25%, hence r = 0.0225.
  • No information about the number of compounding per year, hence n = 1.

Item a:

P = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}

A(8) = 2389.66

Item b:

A(t) = 4000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}

(1.0225)^t = 2

\log{(1.0225)^t} = \log{2}

t\log{1.0225} = \log{2}

t = \frac{\log{2}}{\log{1.0225}}

t = 31.15

Item c:

A(3) = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}

P = \frac{2000}{(1.0225)^3}

P = 1870.85

A similar problem is given at brainly.com/question/24850750

7 0
2 years ago
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