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prisoha [69]
3 years ago
10

Three fair coins are tossed. what is the probability that they are all heads if at least one coin is head,

Mathematics
2 answers:
Olegator [25]3 years ago
4 0
There is your answer hope it helps
\frac{1}{3}
EleoNora [17]3 years ago
3 0

Answer:

1/7

Step-by-step explanation:

There are 8 sample points in the sample space. The sample space is

S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}. The event at least one coin is head is compoused

by seven sample points: {HHH, HHT, HTH, THH, TTH, THT, HTT}, then, to obtain the probability of three heads given that we know that at least one coin is head, we should regard the "new sample space" reduced, i.e., we should consider the set with seven sample points as the new sample space. In the new sample space, just one point corresponds to three heads. Therefore the probability we are seeking is 1 out of 7 or 1/7.

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The bag contains. 1 blue 2 green 3 yellow and 3 red marbles. What is the probability of grabing a red marble without looking.
tekilochka [14]
3/8, you have a three out of eight chance of grabbing a red marble
5 0
2 years ago
David and Peter had $90 and $200 respectively. They were each given an equal amount of money. Then Peter had twice as much money
Aleksandr [31]
20 dollars each! hope it helps.
4 0
2 years ago
Enrique and Yolanda collected 500 pieces of candy on Halloween. They gave half of their candy to charity. Yolanda took 180 piece
777dan777 [17]
The answer would be C. (He counted Yolanda's candy as his own).

This is found by multiplying 500 (starting number of candy) and .64 (percentage divided by a hundred). Thjs would guve you 320, which you would then subtract from the starting number of candy (500) to get 180. 180 is Yolanda's number of candy, which gives you the answer.
4 0
3 years ago
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin
vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

F =450N

x_1 = 30cm

x_2 = 60cm

Required

The work done

First, we calculate the spring constant (k)

F = kx_1

450N = k *30cm

k = \frac{450N}{30cm}

k =15N/cm

So:

F = kx_1

F(x) = 15x

The work done using Hooke's law is:

W =\int\limits^a_b {F(x)} \, dx

This gives:

W =\int\limits^{60}_{30} {15x} \, dx

Rewrite as:

W =15\int\limits^{60}_{30} {x} \, dx

Integrate

W =15 \frac{x^2}{2}|\limits^{60}_{30}

This gives:

W =15 *\frac{60^2 - 30^2}{2}

W =15 *\frac{2700}{2}

W =15 *1350

W =20250N-cm

Convert to Nm

W =\frac{20250Nm}{100}

W =202.50Nm

7 0
3 years ago
dave is painting a fence in his uncle's yard he painted 2 sections of the fence in 30 minutes Dave has 9 sections to paint. if D
Scrat [10]

Answer:

135

Step-by-step explanation:

30÷2≡15

<h3>15×9≡135</h3>
7 0
2 years ago
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