Three fair coins are tossed. what is the probability that they are all heads if at least one coin is head,

Mathematics

2 answers:

Olegator [25]3 years ago

4 0

There is your answer hope it helps
$\frac{1}{3}$

EleoNora [17]3 years ago

3 0

Answer:

1/7

Step-by-step explanation:

There are 8 sample points in the sample space. The sample space is

S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}. The event at least one coin is head is compoused

by seven sample points: {HHH, HHT, HTH, THH, TTH, THT, HTT}, then, to obtain the probability of three heads given that we know that at least one coin is head, we should regard the "new sample space" reduced, i.e., we should consider the set with seven sample points as the new sample space. In the new sample space, just one point corresponds to three heads. Therefore the probability we are seeking is 1 out of 7 or 1/7.

You might be interested in

A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long

wel

Answer: 0.3m/s

Step-by-step explanation:

Height/ velocity

3m/12m per sec

Time= 0.25metres per seconds

To the nearest tenth, 0.3m per seconds

5 0

3 years ago

What is the square root of 50 rounded to the nearest hundredth?

tamaranim1 [39]

Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.

8 0

3 years ago

Identify the diameter of the circular base created by folding the figure into a right cone. HELP ASAP PLEASE!!

Akimi4 [234]

let's notice something, we have a circle with a radius of 12 and one 90° sector is cut off, so only three 90° sectors of the circle are left shaded, so namely the cone will be using 3/4 of that circle.

think of it as, this shaded area is some piece of paper, and you need to pull it upwards and have the cutoff edges meet, and when that happens, you'll end up with a cone-shaped paper cup, and pour in some punch.

now, once we have pulled up the center of the circle to make our paper cup, there will be a circular base, its diameter not going to be 24, it'll be less, but whatever that base is, we know that is going to have the same circumference as those in the shaded area. Well, what is the circumference of that shaded area?

$\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12 \end{cases}\implies C=2\pi 12\implies C=24\pi \implies \stackrel{\textit{three quarters of it}}{24\pi \cdot \cfrac{3}{4}} \\\\\\ 6\pi \cdot 3\implies 18\pi$

well then, the circumference of that circle at the bottom will be 18π, so, what is the diameter of a circle with a circumferenc of 18π?

$\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=18\pi \end{cases}\implies 18\pi =2\pi r\implies \cfrac{18\pi }{2\pi }=r\implies 9=r \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{diameter is twice the radius}}{d=18}~\hfill$