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uysha [10]
1 year ago
11

A survey asked 20 mobile phone dealers how many mobile phones were sold during the previous week. Their answers are displayed in

the Box-and-Whisker Plot and the Stem-and-Leaf Plot shown. Which graph can be used to find the mode? What is the mode of the data set? A. Stem-and-Leaf Plot, Mode: 34 B. Stem-and-Leaf Plot, Mode: 42 C. Box-and-Whisker Plot, Mode: 43 D. Box-and-Whisker Plot, Mode: 38
ASAP 100 POINT AND BRAINLIST
Mathematics
1 answer:
Sidana [21]1 year ago
8 0

The best type of chart for quickly deriving the mode of a sample data is called the Stem-and-Leaf Plot.

<h3>What is a Stem-and-Leap Plot?</h3>

In statistics, the Stem-and-Leaf Plot is an easy-to-make easy-to-read kind of graph that is derived from the table holding the sample data.

The Box-and-Whisker Plot on the other hand is best for visually depicting the five-number summary of any set of data, which are:

  • Minimum
  • First Quartile
  • Median (Second Quartile)
  • Third Quartile; and
  • Maximum.

It is to be noted that referenced plots are not indicated hence, the general answer.

Learn more about Stem-and-Leaf Plot at:
brainly.com/question/8649311
#SPJ1

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If the profits in your consulting business increase by 8​% one year and decrease by 2% the following​ year, your profits are up
olchik [2.2K]

Answer:

not true....

assume $100 start.

in year 1 you are at $108 (up 8%)

in year 2  $108(.98) ... that is 2% down = 105.84...

thus your profit is up only 5.84% over the two years

Step-by-step explanation:

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2 years ago
Which figure would be Topologically equivalent to a square?
aleksklad [387]
The figure C is equivalent to a square
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Four possibly winning numbers for a lottery—AB-4536, NH-7812, SQ-7855, and ZY-3221—
antoniya [11.8K]
We first of all calculate our sample size. The number of ways of generating two letter and four digits in a way that repeatition is allowed is:
26^2 x 10^4 = 676 x 10000 = 6,760,000.
Therefore, there are 6,760,000 possible number combinations for the lottery.

Probability of winning the first prize = 1/6,760,000
Probability of winning the second prize is 2/6,760,000 = 1/3,380,000
Probability of winning the third prize is 10/6,760,000 = 1/676,000
Probability of winning nothing is (6,760,000 - 13)/6,760,000 = 6,759,987/6,760,000                 *[there are 13 winnings in all]

Expected winning from the lottery = (1/6,760,000) x (100,000 - 0.33) + (1/3,380,000) x (50,000 - 0.33) + (1/676,000) x (1,000 - 0.33) + (6,759,987/6,760,000) x (-0.33) = 0.0148 + 0.0148 + 0.0015 - 0.3300 = -0.30

Therefore, the expected winning is a loss of 30 cents.
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6 0
3 years ago
I need help asap!
lisabon 2012 [21]

Write an equation and solve it. Call the length of the shorter piece "x", in this case, the longer piece is "3x". The sum of the two is equal to 116 inches.

4 0
3 years ago
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I have 7 different geography textbooks and 4 different chemistry textbooks. In how many ways can I line the 11 textbooks on a bo
saveliy_v [14]

Answer:

120960

Step-by-step explanation:

We get 11 books   7 of geography  and  4  of chemistry

We need to line all of them  with 2 constraints

1.-three of the geography must be: 1 in the middle and in each end, then we already have

C₄,₃   =   4! / ( 4 - 3 ) !     C₄,₃   =  4*3*2*1

C₄,₃   =   24  different ways

Now we have 7 books of chemistry. To place them we get

P₇  = 7!     P₇ =  7*6*5*4*3*2*1         P₇  = 5040

Now the total number will be

C₄,₃* P₇  =  120960

7 0
3 years ago
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