Answer: last option
Step-by-step explanation:
You know that the weight of his pumpkin 4.9 pounds and that, if he guesses its weight within 0.3 pounds, he will get the pumpkin for free.
Then, to find the minimum weight he can guess in order to get his pumpkin for free, it's necessary to write the expression:
Rewriting it:
To find the maximum weight he can guess in order to get his pumpkin for free, it's necessary to write the expression:
Rewriting it:
Answer:
Option A -
Step-by-step explanation:
We have given the expression
We have to find the value of the expression ?
Solution :
Step 1 - Write the expression
Step 2 - Applying symbol rule i.e. multiplication of positive into negative is always negative,
Step 3 - Solve
Therefore, The value of the expression is
So, Option A is correct.
Answer:
a) There is a 1.21% probability that both contain diet soda.
b) There is a 79.21% probability that both contain diet soda.
c) is unusual,
is not unusual
d) There is a 19.58% probability that exactly one is diet and exactly one is regular.
Step-by-step explanation:
There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And is the probability of X happening.
A number of sucesses is considered unusually low if
and unusually high if
In this problem, we have that:
Two cans are randomly chosen, so
Two out of 18 cans are filled with diet coke, so
a) Determine the probability that both contain diet soda. P(both diet soda)
That is P(X = 2).
There is a 1.21% probability that both contain diet soda.
b)Determine the probability that both contain regular soda. P(both regular)
That is P(X = 0).
There is a 79.21% probability that both contain diet soda.
c) Would this be unusual?
We have that is unusual, since
For P(X = 0), it is not unusually high nor unusually low.
d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)
That is P(X = 1).
There is a 19.58% probability that exactly one is diet and exactly one is regular.