The second cylinder is taller correct?
8 in < 11 in
If the height is also larger, the base is most likely larger too.
Wouldn't the largest cylinder have a Larger surface area?
Answer:
3−y
2. 8
4.2bh
Step-by-step explanation:
5(2x+y)=15
2 Divide both sides by 55.
2x+y=\frac{15}{5}2x+y=
5
15
3 Simplify \frac{15}{5}
5
15
to 33.
2x+y=32x+y=3
4 Subtract yy from both sides.
2x=3-y2x=3−y
5 Divide both sides by 22.
x=\frac{3-y}{2}x=
2
1. 3−y
2. 8
2.Add 2y2y to both sides.
x=-8+2yx=−8+2y
2 Regroup terms.
x=2y-8x=2y−8
Answer:
r = 6 in
Step-by-step explanation:
= 
r²h/3 = 216
r² (18/3) = 6 r² = 216
r² = 216/6 = 36
r = 6
Answer:
Option B
Step-by-step explanation:
Given quadratic equation is,
12a² + 9a + 7 = 0
By comparing this equation with standard quadratic equation,
hx² + kx + c = 0
h = 12, k = 9 and c = 7
By using quadratic formula,
a = 
= 
= 
= 
= 
a = 
Therefore, Option B will be the correct option.
Answer:
The length of the sides of the triangle are as follow: Two sides are 14.4 inches long and the shortest is 7.2 inches.
Step-by-step explanation:
P = 36in // perimeter of triangle
P = A + B + C //equation for perimeter of a triangle
A = B or B = A //Showing that two sides are equal in length
A = 2C and B = 2C //Showing that the two equal sides are each doubled of the shortest side
C = A/2 and C = B/2 //Showing the same thing as the top, but in terms of the shortest side
Solve for C //First we solve for the shortest side as it's easiest
36 = A + B + C
36 = 2C + 2C + C //Use substitution for A and B
36 = 5C
C = 7.2in
Solve for A
A = 2C
A = 2(7.2) //Use what we solved for C
A = 14.4in
Solve for B
B = A
B = 14.4in //Same as A
Check Work
P = A + B + C
P = 14.4 + 14.4 + 7.2
P = 36
