Answer:
149 engines in 9th year
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
From a look at the photo and the data plot can be represented by the function, so we can pick 2 points in our given graph
- (x1, y1) = (2,60)
- (x2, y2) = (5,99)
The standard form of a linear equation is:
y = mx + b where:
- m is the slope
- b is the y-intercept
We know the slope of the function can be found as following:
so in this situation we have:
<=>
=> y = 13x + b (1)
Because the line goes through point (2,60) so we substitute it into (1):
60 = 13*2 + b
<=> b = 60 - 26 = 34
=> y = 13x + 34
Now we will substitute x=9 to find the engines produced by company in 9th year as:
Hence, the company will produce 149 engines in 9th year
C.
I used the rise/run method you rise 13 and run -11 which means on the x axis you move 11 spaces to the left and on the y axis you move 13 spaces up.
K+3 3/4=5 2/3-1 1/3
k+3 3/4=4 1/3
lets find the lcm first then multiply both sides by it but first change it to improper fraction
LCM is 12
[k+15/4]=[13/3]12
12k+45=52
12k=7
k=7/12