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3 years ago

What does x equal to

Mathematics

1 answer:

Slav-nsk [51]3 years ago

3 0

If that is a rhombus as it says it is, then the diagonals are perpendicular to one another, meaning where they meet, they form right angles. Therefore, angle x is a 90 degree angle.

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6. what is the parimeter of triangle ABC<br>8. What is the value of x

nalin [4]

<u>Answer:</u>

Perimeter = 20 units

x = 120°

<u>Step-by-step explanation:</u>

We are given a triangle ABC with known side lengths for all three sides and an inscribed circle.

We are to find the perimeter of triangle ABC and the value of x.

Perimeter of triangle ABC = 2 + 2 + 5 + 5 + 3 + 3 = 20 units

The kite shape at the end is a quadrilateral which has a sum of angles of 360 degrees.

Two out of four angles are right angles and one is 60 so we can find the value of x.

x = 360 - (90 + 90 + 60) = 120°

7 0

3 years ago

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What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?

anyanavicka [17]

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$f( - 4) = 4( - 4) + 9 = - 7$

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$f( - 2) = 4( - 2) + 9 = 1$

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$f(0) = 4(0) + 9 = 9$

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$f(2) = 4(2) + 9 = 17$

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Thus ;

R = { - 7 , 1 , 9 , 17 }

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The correct answer is (( D )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

3 0

3 years ago

Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

We have,

$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

$y=-2x^2+10x-7$ ...(i)

Here, $a=-2,b=10,c=-7$ .

$\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}$

$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

$y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7$

$y=\dfrac{-50}{4}+25-7$

$y=\dfrac{-25}{2}+18$

On further simplification, we get

$y=\dfrac{-25+36}{2}$

$y=\dfrac{11}{2}$

So, the vertex of the given quadratic equation is $\left(\dfrac{5}{2},\dfrac{11}{2}\right)$ .

Therefore, the correct option is A.

3 0

3 years ago

Can someone help me with these problems?

arlik [135]

1: 200-75= r

2: 73-29= v
73-29=44
v=44

6 0

4 years ago

Read 2 more answers

10 points for answering!<br> What is the answer to 13, 14, and 15?

ki77a [65]

Step-by-step explanation:

$\implies\sf{ {x}^{2} = 144 } \\ \\ \implies\sf{ x = \pm \sqrt{144} } \\ \\ \implies\sf{ x = \pm 12 }$

$\implies\sf{ {x}^{2} = \dfrac{25}{289} } \\ \\ \implies\sf{ x = \pm \sqrt{ \frac{25}{289} } } \\ \\ \implies\sf{ x = \pm \frac{5}{17} }$

$\implies\sf{ {x}^{3} = 216 } \\ \\ \implies\sf{ x = \sqrt[3]{216} } \\ \\ \implies\sf{ x = 6 }$

4 0

3 years ago