the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
c. The expected values of R and S will be equal, and the variability of R will be greater than the variability of S.
Step-by-step explanation:
This is Central Limit Theorem concept in which independent variables are added and form a normal distribution. The random sample of n sample size is selected which calculates normally distributed mean and variance. The expected value of samples distributor will be higher than the sample distribution.
Answer:
and 
Step-by-step explanation:
The LCM of 35 and 10 is 70.
35×2=70
10×7=70
You got to multiply 3 with 2 and 1 with 7 to make 6/70 and 7/70.
Answer: 2hrs?
Step-by-step explanation: 3-2=1+1 hour she took alone = 2hrs
The way you find area is multiplying width times height, so you have to multiply 15 by 4 which equals 60. Therefore the answer is 60
