At the 2/8 part, just use the quadratic formula. If you use it, you should get the other two zeroes:
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2 answers:
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The area:
Substitution: u = - 6 x
du = - 6 dx
dx = -1/6 du
∫ -1/6 e^(u) du = - 1/6 e^(u) = - 1/6 e^(-6x)
= π / 3
Substitution: u = - 6 x
du = - 6 dx
dx = -1/6 du
∫ -1/6 e^(u) du = - 1/6 e^(u) = - 1/6 e^(-6x)
= π / 3