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Ivahew [28]
3 years ago
8

EXTRA POINTS PLEAS HELP ME !!!!!!!!!!!! :3 ◑ω◐ 14 points if you can help ◑ω◐

Mathematics
2 answers:
Ugo [173]3 years ago
5 0

Answer:

The answer is

(A. )1\50 - -(1 3/4) C. 0.50 + 1.75

Step-by-step explanation:

I had the same question 5 minutes ago hope this helps

VikaD [51]3 years ago
3 0
A is . 1/50
lmk if you need any other help :)
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a meal cost $15. we gave the waiter $18 and told him that the difference was his tip. what percent of the cost of the meal was t
Stella [2.4K]
18 - 15 = 3
3/15 = n/100
15n = 300
n = 20
6 0
2 years ago
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What is the y-intercept of the graph below? HELP SOMEONE!!​
Trava [24]

Answer:

the y-intercept is (0,75)

Step-by-step explanation:

the y-intercept is where the line crosses the y-axis.

5 0
2 years ago
-17+4a<br><br> Please solve.
ikadub [295]

Answer:

-17+4a=0

-17= -4a(-,-=+)

a=17/4

7 0
2 years ago
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A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha
White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

\frac{dB}{dt} = rB-k

\Rightarrow \frac{dB}{dt} - rB=-k.......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor =e^{\int p(t) dt

                                     =e^{\int (-r)dt

                                     =e^{-rt}

Multiplying the integrating factor the both sides of equation (1)

e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}

\Rightarrow  e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt

Integrating both sides

\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt

\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C        [ where C arbitrary constant]

\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}

Initial condition B=7864 when t =0

\therefore 7864= \frac{k}{r} - Ce^0

\Rightarrow  C= \frac{k}{r} -7864

Then the general solution is

B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}

\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

                                                 =$1573.17

4 0
3 years ago
What is the surface area of the cylinder? Express the answer in terms of pi
Sholpan [36]
Bonjour,

answer ≈ 522.92

working
A= 2πrh+2πr^2
=2 x π x 4 x 18+2 x π x 4^2
≈552.92031
4 0
3 years ago
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