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Answer:
protein is the right answer
Answer: If this population were in equilibrium and if the sickle-cell allele is recessive, the proportion of the population susceptible to sickle-cell anemia under typical conditions should be 0.20
Explanation: Hardy-Weinberg law provides an equation to relate genotype frequencies and allele frequencies in a randomly mating population. The equation is;
p² + 2pq + q² = 1
For 2 alleles such as A and a, where
p² = homozygous dominant
q² = homozygous recessive and
2pq = heterozygous
From the question, it is said that the sickle-cell allele (SS) constitutes 20% (that is, 20/100) of the hemoglobin alleles in the human gene pool and it is also said to be the homozygous recessive allele.
Therefore, q² = 20/100 = 0.20
Genetic variation describes the genetic differences among individuals of the same species that are naturally occurring. <span>Each genotype within a population usually has different degrees of fitness to an environment. Mating between same species with favored genes guarantees survival of the population in their chosen environment. As the environment changes, the mating behavior between species may again change resulting to a different gene pool to guarantee survival. </span>
