Question

What is the equation in point -slope form of a line that passes trough the points (3,-5) and (-8,4)

Answer 1

Answer:

The equation in point - slope form of a line that passes through the points (3,-5) and (-8,4) is: y-(-5) = -(9/11) (x-3) or y+5 = -(9/11) (x-3)

Step-by-step explanation:

P1=(3,-5)=(x1,y1)→x1=3, y1=-5

P2=(-8,4)=(x2,y2)→x2=-8, y2=4

Equation in Point-Slope Form: y-y1=m(x-x1)

Slope: m=(y2-y1)/(x2-x1)

Replacing the known values:

m=[4-(-5)] / (-8-3)

m=(4+5) / (-11)

m=(9) / (-11)

m=-(9/11)

Equation in the point - slope form:

y-(-5) = -(9/11) (x-3)

y+5 = -(9/11) (x-3)