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andreev551 [17]
2 years ago
14

\textbf{Help with this question } " alt="\large \textbf{Help with this question } " align="absmiddle" class="latex-formula">~
\textsf{For an Isosceles prism of Angle A and} \textsf{Refractive index}\: \sf \mu ,\textsf{ it is found that }\textsf{the angle of minimum deviation }\sf{ \delta_m = A.}\textsf{Then which of the following is/are correct}

\textbf{[ Multiple choice ]}

\textsf{(a) At minimum deviation, the incident}\sf{ angle \: \:i_1 }\textsf{and the retracting angle} \sf{r_1}\textsf{ at the first retracting surface are} \textsf{related by }\sf{ r_1 = (i_1/2) }

\textsf{(b) For this prism, the retracting index}\sf{ \mu}\textsf{ and the angle of Prism A are related as}
\sf{ A = \dfrac{1}{2}cos^{-1}\bigg\{\dfrac{\mu}{2}\bigg\}}

\textsf{(c) For this prism, the emergent ray at the }\textsf{second surface will be tangential to the }\textsf{surface when the angle of incidence at the}\textsf{ first surface is}\: \sf{ i_1 = sin^{-1} \bigg[sinA \sqrt{4cos²\dfrac{A}{2}-1}-cosA\bigg]} [tex] \textsf{(d) For the angle of incidence}\sf{ i_1 = A,} \textsf{the ray}\textsf{ inside the prism is parallel to the base}\textsf{ of the prism}

Please provide explanation ~

​
Physics
1 answer:
PIT_PIT [208]2 years ago
8 0

<h3>Hi there !</h3><h2>Option A is correct </h2>

<h3> Please refer the attachment for explanation</h3><h2>Stay safe, stay healthy and blessed</h2><h2>Have a marvelous day</h2><h2>Thank you</h2>

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The difference in the pressure between the inside and outside will be 369.36 N/m²

<h3>What is pressure?</h3>

The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.

It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.

The given data in the problem is;

dP is the change in the presure=?

Using Bernoulli's Theorem;

\rm  \rho\frac{V^2_{12}}{2} +P_1= \rho \frac{V^2_{22}}{2} +P_2 \\\\\ P_2-P_1=\rho \frac{v_2^2-v_1^2}{2} \\\\  P_2-P_1= 1.21 \times \frac{17.4^2-0}{2} \\\\  \triangle p=369.36 \ N/m^2

Hence, the difference in the pressure between the inside and outside will be 369.36 N/m²

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brainly.com/question/356585

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3 0
2 years ago
A 2498 kg car is moving at 17.1 m/s slams on its brakes and slows to 2.6 m/s. What is the magnitude (absolute value) of the impu
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Answer:

<em>J=36221 Kg.m/s</em>

Explanation:

<u>Impulse-Momentum Theorem</u>

These two magnitudes are related in the following way. Suppose an object is moving at a certain speed v_1 and changes it to v_2. The impulse is numerically equivalent to the change of linear momentum. Let's recall the momentum is given by

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m=2498\ kg,\ v_1=17.1\ m/s,\ v_2=2.6\ m/s

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J=-36221 Kg.m/s

The magnitude of J is

J=36221 Kg.m/s

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3 years ago
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Refer to the figure below.
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Answer:

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