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2 years ago

Helpp pleaseeeeee …..

Physics

1 answer:

Lilit [14]2 years ago

8 0

Answer:

300 cos 30 = 40 a + 40 * .2 * 10

Total force = mass * acceleration + frictional force

260 = 40 a + 80

a = 180 / 40 = 4.5 m/s^2

Check:

15 a + 15 * 10 * .2 = T acceleration of 15 kg block (assuming a = 4.5)

T = 15 (4.5) + 30 = 97.5 force required to accelerate 15 kg block

260 - 97.5 = 162.5 net force on 25 kg block

162.5 = 4.5 (25) + 25 * 10 * .2

162.5 = 112.5 + 50 = 162.5

4.5 m/s^2 checks out as correct

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Gemiola [76]

Answer:

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dist = 40m

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3 years ago

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3 years ago

Read 2 more answers

An unpolarized beam of light with an intensity of 4000 W/m2 is incident on two ideal polarizing sheets. If the angle between the

erastova [34]

Answer:

The intensity is $I_2 = 1654 \ W/m^2$

Explanation:

From the question we are told that

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$I_2 = \frac{I_o}{2}$

substituting values

$I_1 = \frac{4000}{2}$

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Then the intensity of incident light emerging from the second polarizer is mathematically represented by Malus law as

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4 0

4 years ago

A bullet is fired through a board 13.0 cm thick in such a way that the bullet's line of motion is perpendicular to the face of t

GREYUIT [131]

Answer:

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t = Time taken

u = Initial velocity = 560 m/s

v = Final velocity = 460 m/s

s = Displacement = 13 cm

a = Acceleration

From the equation of motion we have

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{460^2-560^2}{2\times 13\times 10^{-2}}\\\Rightarrow a=-392307.6923\ m/s^2$

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5 0

3 years ago