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3 years ago

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11 Initially, a single resistor R 1 is wired to a battery. Then resistorR 2 is added in parallel. Are (a) the potential differen

ce across R 1and (b) the current i 1 through R 1 now more than, less than, or thesame as previously?

1 answer:

d1i1m1o1n [39]3 years ago

8 0

Answer:

Explanation:

Since , resistances are joined in parallel , potential difference across either of R₁ or R₂ will be same , and it will be equal to emf of the cell provided no internal resistance exists in the cell.

Since potential difference across R₁ is equal to emf and resistance is R₁ , current through it too will be same as that in the previous case.

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2 years ago

Two football players are attempting to tackle each other. If one football player has a mass of 100 kg and pushes with a force of

Vaselesa [24]

Answer:

is it 20kg. Two opposing forces pushing onto each other

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2 years ago

Two loudspeakers are 1.60 m apart. A person stands 3.00 m from one speaker and 3.50 m from the other. (a) What is the lowest fre

VMariaS [17]

Answer:

Explanation:

Given

Distance between two loud speakers $d=1.6\ m$

Distance of person from one speaker $x_1=3\ m$

Distance of person from second speaker $x_2=3.5\ m$

Path difference between the waves is given by

$x_2-x_1=(2m+1)\cdot \frac{\lambda }{2}$

for destructive interference m=0 I.e.

$x_2-x_1=\frac{\lambda }{2}$

$3.5-3=\frac{\lambda }{2}$

$\lambda =0.5\times 2$

$\lambda =1\ m$

frequency is given by

$f=\frac{v}{\lambda }$

where $v=velocity\ of\ sound\ (v=343\ m/s)$

$f=\frac{343}{1}=343\ Hz$

For next frequency which will cause destructive interference is

i.e. $m=1$ and $m=2$

$3.5-3=\frac{2\cdot 1+1}{2}\cdot \lambda$

$\lambda =\frac{1}{3}\ m$

frequency corresponding to this is

$f_2=\frac{343}{\frac{1}{3}}=1029\ Hz$

for $m=2$

$3.5-3=\frac{5}{2}\cdot \lambda$

$\lambda =\frac{1}{5}\ m$

Frequency corresponding to this wavelength

$f_3=\frac{343}{\frac{1}{5}}$

$f_3=1715\ Hz$

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3 years ago

The function of a capacitor in an electric circuit is to

jok3333 [9.3K]

Answer: B. store electric charges.

Explanation: I JUST TOOK THE PF EXAM AND I GOT IT CORRECT!!!!

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3 years ago

A small first-aid kit is dropped by a rock climber who is descending steadily at 1.9 m/s. After 2.4 s, what is the velocity of t

Genrish500 [490]

Answer:

$v=-21.65 m/s$

Explanation:

From the exercise we have:

$v_{o}=1.9m/s\\ g=9.81 m/s^{2}\\ t=2.4s$

To find the velocity after 2.4s we need to use the following formula:

$v=v_{o}+gt$

$v=1.9m/s-(9.81m/s^{2})(2.4s)=-21.65m/s$

The negative sign means that the kit is going down.

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2 years ago

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