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Inessa05 [86]
3 years ago
13

11 Initially, a single resistor R 1 is wired to a battery. Then resistorR 2 is added in parallel. Are (a) the potential differen

ce across R 1and (b) the current i 1 through R 1 now more than, less than, or thesame as previously?
Physics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

Explanation:

Since , resistances are joined in parallel , potential difference across either of R₁ or R₂ will be same , and it will be equal to emf of the cell provided no internal resistance exists in the cell.

Since potential difference across R₁ is equal to emf and resistance is R₁ , current through it too will be same as that in the previous case.

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GarryVolchara [31]

Answer:

1) Half Girlfriend

2) I am Malala

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4)I too had a love story

5)Your Dream are Now Mine

Explanation:

I don't have a same pattern to read but mostly of romantic and fiction. I read less autobiographies but when I read I am Malala , it was an inspiring one.My favorite type of reading is romantic types and least favorite is non fiction especially History

6 0
3 years ago
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Setler [38]
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3 years ago
The moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is
sleet_krkn [62]

Answer:

I = I₀ + M(L/2)²

Explanation:

Given that the moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is I₀.

The parallel axis theorem for moment of inertia states that the moment of inertia of a body about an axis passing through the centre of mass is equal to the sum of the moment of inertia of the body about an axis passing through the centre of mass and the product of mass and the square of the distance between the two axes.

The moment of inertia of the body about an axis passing through the centre of mass is given to be I₀

The distance between the two axes is L/2 (total length of the rod divided by 2

From the parallel axis theorem we have

I = I₀ + M(L/2)²

5 0
3 years ago
I need help to figure out how to solve this problem and solve it!!!
wariber [46]

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4 0
3 years ago
Read 2 more answers
The horizontal force exerted between the tires of a 500kg car and the ground is 980N. if the car starts from rest, how far will
Maksim231197 [3]

Answer:

Explanation:

d = ½at²

d = ½(F/m)t²

d = ½(980/500)5²

d = 24.5 m

6 0
2 years ago
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