Answer:
The correct answer is NO.
Step-by-step explanation:
John is graphing two lines with equations say ax + by + c = 0 and dx + ey +f =0 on his graphing calculator.
For John to get a unique solution the coefficients should follow the following condition 
. So when he plots the lines he get an intersecting pair of lines.
For John to get no solution the coefficients should follow the following condition 
. When we plot in this case we get two parallel lines.
For John to get an infinite many solution the coefficients should follow the following condition 
. And when we plot the lines in this case we get one line superimposed on the other.
Since after graphing, John sees only one line, the lines must have superimposed on one another giving John an infinite number of solutions.
Answer:
Distance of JK = 15 unit
Step-by-step explanation:
Given:
J(4,8)
K(-1,-2)
Find:
Distance of JK
Computation:
Distance = √(x₂-x₁)² + (y₂-y₁)²
Distance of JK = √(-1-4)² + (-2-8)²
Distance of JK = √25 + 100
Distance of JK = √125
Distance of JK = 15 unit
Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper = 
sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining = 
= 
Using algebraic formula: 
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.
I hope this is right i think the answer is 40
