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kherson [118]
1 year ago
12

Which is the graph of y=(x-1)4-3?

Mathematics
1 answer:
Bumek [7]1 year ago
4 0

Answer:

There is no graph attached but it would look like this

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What is the quotient of 99 divided by 9081
Artist 52 [7]

Hello from MrBillDoesMath!

Answer:

11/ 1009   (.0109 approximately)

Discussion:

99/9081 =                               => as 9081 = 9 * 1009 = 3 * 3 * 1009

99/ ( 3 * 3 * 1009)  =

(99/(3*3)) * (1/1009) =

(99/9)  * (1/1009)  =

11/ 1009 =

.0109 approximately


Thank you,

MrB

6 0
3 years ago
Read 2 more answers
There are 10 roller coasters at 6 flags, and you only have time to ride 3 before the park closes. How many different ways can yo
Charra [1.4K]

Answer:

  120

Step-by-step explanation:

If order doesn't matter, there are 10 ways to chose the first ride, 9 ways to choose the second, and 8 ways to choose the third. This product (720) has you riding the same 3 coasters in 6 different orders. Dividing by 6 gives ...

  720/6 = 120 different combinations of roller coasters

_____

This number might be written as 10C3 (choose 3 from 10). The meaning of that notation is ...

  nCk = n!/(k!(n-k)!)

  10C3 = 10!/(3!·7!) = 10·9·8/(3·2·1) = 120

4 0
3 years ago
Read 2 more answers
the following data represent the number of people aged 25-64 years covered by health insurance (private or government) in 2018.
astraxan [27]

Answer:

mean = find the total of people in such data by adding up all the totals of people represented by each age then  divide that total by 2.

mean = with cumulative or frequency graphs if the numbers range individually like 25-30 and 30-35 etc and so on then you take the midpoint age and multiply it by the frequency number in new column add up both columns then divide by smaller total.

mean = histogram total number of data ie) from 270 people (80 x 0 = 0), (40 x 2 = 0) and so on multiplying the frequency. then add them all up in new column ie) 380 among 270 people = 1.4  

mode = histogram highest box

median = histogram add up all data number divided by 2 and can draw this on graph as they sort of are in order ie) 15 to the left and 15 to the right

To find standard deviation you need the copulative formula and the notation change for sample shows the small m and s to represent standard deviation ie) m-n is a notation difference for samples of population's

n = number of scores ie)  = 50  

Ex = then sum of x  = would be the collective total  ie) = 270

m = 270/50 = 5.4

Ex^2 = 270 x 270 = 72900   (the square of the total population)

SS = Sum of squares = 72,900 - ( 270^2 / 50) are all the variables.

is the formula  = 71,442

the root of SS -1

S^2 = 270 / (50 -1) =  270/49 = 5.51

S = sqrt S^2 = sqrt SS /n-1 = sq rt 50 = and you get your answer here.

Standard Deviation on data example here shown is;

S = sqrt 5.51 = sqrt 71442 / n-1 = sq rt 71442/ 50-1 = sq rt 71442/49 = 38.1837662  from a 270 population that exists with 50 age group 25 -75 to show the ease here and how to remember.

Just retrace and where 270 is change for total

Where 50 is put 64-25 = 39

and where n-1 is put 39-1 and always subtract first before dividing as the formula protects the brackets as seen in bold.

As your very last formula is S = SS/n-1

Step-by-step explanation:

5 0
2 years ago
Jake used integers to record his costs and earnings from selling homemade muffins. He spent $16 on ingredients. He earned $125 f
denis23 [38]

-16 and 125

Step-by-step explanation: hope this helped!

6 0
3 years ago
Read 2 more answers
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
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