Question

Help me please!!! 10 points!!

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's solve for x ~

We can apply Trigonometric ratios here, since the given triangle is a right angled triangle

so,

$\qquad \sf \dashrightarrow \: \sin(30) = \dfrac{ \sqrt{3} }{x}$

$\qquad \sf \dashrightarrow \: \dfrac{1}{2} = \dfrac{ \sqrt{3} }{x}$

$\qquad \sf \dashrightarrow \:x = 2 \times \sqrt{3}$

$\qquad \sf \dashrightarrow \:x = 2 \sqrt{3}$

i hope you you understood

Answer 2

Answer:

2√3

Step-by-step explanation:

The shown triangle is a 30-60-90 special right triangle due to the right angle and the thirty degree angle(the other angle has to be 60 degrees).

The hypotenuse of a 30-60-90 triangle is twice the leg opposite the 30 angle. The leg opposite the 30 degree angle is √3, so x would be 2√3.