Please help for brainliest
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Hello,
The formula for finding the area of a circular region is:
then:
With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.
Now we can find its area:
![A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)](https://tex.z-dn.net/?f=A_%7B2%7D%3D2%2A%20%5Cfrac%7Bb%2Ah%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20A_%7B2%7D%3D%20%5Br%2Asen%2840%29%5D%5Br%2Acos%2840%29%5D%5C%5C%20%20%5C%5CA_%7B2%7D%3D%20r%5E%7B2%7D%2Asen%2840%29%2Acos%2840%29)
The subtraction of the two areas is 100cm^2, then:
Answer: r= 1.59cm
The formula for finding the area of a circular region is:
then:
With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.
Now we can find its area:
The subtraction of the two areas is 100cm^2, then:
Answer: r= 1.59cm
I'm guessing the function is
which, split into partial fractions, is equivalent to
Recall that for we have
With some rearranging, we find
valid for , or
, and
valid for , or
.
So we have
Taken together, the power series for can only converge for
, or
.