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1 year ago

What is reacitivty series, and how you can access reactivity of metals...

1 answer:

8 0

In Chemistry, a reactivity series of metals , also known as the activity series refers to the arrangement of metals in the descending order based upon their reactivity .

Salient Features :-

The metal at the top of the reactivity series are powerful reducing agents since they are easily oxidized.
The reducing ability of metals grows weaker while traversing down the series.
The electro-positivity of metals also reduces while moving down the reactivity series.
Metals that are placed higher on the reactivity series have the ability to displace metals that are placed lower in the series.

The metal reactivity series is given below :-

To access the reactivity of metal , from the given reactivity series identify any of the metal and locate the reactivity based upon the choice of reactivity. The metal at the top (Potassium) is most reactive and the metal at the bottom (Platinum) is the least reactive.

To learn more about metal reactivity series visit -

brainly.com/question/16072297

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If the human body were a car, glucose would be:

NeTakaya

If the human body were a car, glucose would be the gasoline.
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2 years ago

Caculate the number if moles of the following: 800. g of Ca

Maru [420]

Mole is equal to mass of the element divided by molar mass of the element. that is
mole=mass/molar mass
From periodic table calcium has a molar mass of 40 g/mol
moles is therefore =800g/40g/mol=20moles

3 0

2 years ago

What’s is the answer

julsineya [31]

Answer:

The answer is the third one which is 24 (glucose)

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2 years ago

Hund's rule states that electrons must spread out within a given subshell before they can pair

Temka [501]

Answer:

Groups 14, 15, and 16 have 2,3, and 4 electrons in the p sublevel (p sublevel has 3 "spaces" AKA orbitals), because Hunds says one in each orbital before doubling up if you had 2 electrons, group 14, they would both be in the first orbital, with 3 electrons, group 15, two in the first orbital one in the 2nd none in the 3rd. With 4 electrons, group 16, then you would have 2 in the first 2 orbitals and NONE in the 3rd.

Explanation:

If you are in group 13 you only have 1 electron so it can only be in one orbital. with group 17, you have 5 electrons, so 2 in the first 2 in the second and 1 in the 3rd, correct for Hunds rule anyway. Noble gasses, group 18, have 6 elecctrons, so every orbital is full any way you look at it.

6 0

2 years ago

Calculate the wavelength, in nanometers, of the spectral line produced when an electron in a hydrogen atom undergoes the transit

Lapatulllka [165]

Answer: The wavelength of spectral line is 656 nm

Explanation:

To calculate the wavelength of light, we use Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2} \right )$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $1.097\times 10^7m^{-1}$

$n_f$ = Final energy level = 2

$n_i$ = Initial energy level = 3

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.524\times 10^6m^{-1}}=6.56\times 10^{-7}m$

Converting this into nanometers, we use the conversion factor:

$1m=10^9nm$

So, $6.56\times 10^{-7}m\times (\frac{10^9nm}{1m})=656nm$

Hence, the wavelength of spectral line is 656 nm

6 0

2 years ago