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xxTIMURxx [149]
2 years ago
14

A machine fills containers with 35 ounces of raisins. After the containers are filled, another machine weighs them. If the conta

iner's weight
differs from the desired weight of 35 ounces by more than two ounces, the container is rejected. Which graph could be used to determine
minimum and maximum acceptable weights for the containers?

Mathematics
1 answer:
EleoNora [17]2 years ago
7 0

Answer:

a think only thing thats close to my data

Step-by-step explanation:

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Please help with 2 in the picture.
Ierofanga [76]

Answer:

4

Step-by-step explanation:

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2 years ago
Exercise 2.6.3. If (xn) and (yn) are Cauchy sequences, then one easy way to prove that (xn + yn) is Cauchy is to use solution th
Montano1993 [528]

Answer and Step-by-step explanation:

The answer is attached below

3 0
3 years ago
If a person can complete a job in 8 hours and his/her friend needs 6 hours to do the same job, what portion of the job would the
swat32

Answer:

1 hour 20 minues

Step-by-step explanation:

I calculated it

6 0
3 years ago
Find the 90% confidence interval for the variance and standard deviation of the ages of seniors at oak park college if a random
san4es73 [151]
Given that the standard deviation, s = 2.3 and that there are 24 students, thus the degree of freedom is 24 - 1 = 23.

For 90% confidence interval, \alpha =0.1 and \frac{ \alpha }{2} =0.05

From the chi-square table, the value of \chi^2_{1- \frac{ \alpha }{2} }=\chi^2_{0.95}=35.172 and the value of \chi^2_{ \frac{ \alpha }{2} }=\chi^2_{0.05}=13.091.

The 90% confidence interval for \sigma^2 is given by:

\frac{(n-1)s^2}{\chi^2_{1- \frac{ \alpha }{2} }} \ \textless \ \sigma^2\ \textless \ \frac{(n-1)s^2}{\chi^2_{ \frac{ \alpha }{2} }} \\  \\ = \frac{(24-1)(2.3)^2}{35.172} \ \textless \ \sigma^2\ \textless \ \frac{(24-1)(2.3)^2}{13.091} \\  \\ = \frac{23(5.29)}{35.172} \ \textless \ \sigma^2\ \textless \ \frac{23(5.29)}{13.091} = \frac{121.67}{35.172} \ \textless \ \sigma^2\ \textless \  \frac{121.67}{13.091}  \\  \\ =3.46\ \textless \ \sigma^2\ \textless \ 9.29

And the 90% confidence interval for \sigma is given by:

\sqrt{\frac{(n-1)s^2}{\chi^2_{1- \frac{ \alpha }{2} }}} \ \textless \ \sigma\ \textless \ \sqrt{\frac{(n-1)s^2}{\chi^2_{ \frac{ \alpha }{2} }}} \\  \\ = \sqrt{3.46} \ \textless \ \sigma\ \textless \  \sqrt{9.29} =1.86\ \textless \ \sigma\ \textless \ 3.05
3 0
3 years ago
A roofer measures a run of 4 feet for each 2 feet of rise on a roof. what is the pitch, or slope, of the roof
kobusy [5.1K]
Rise/Run=2/4= 1/2, the answer would be 1/2.
6 0
4 years ago
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