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nadezda [96]
3 years ago
5

Express 1.454545.........+0.4555555.............in the form of p/q,

Mathematics
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

1.91010005

Step-by-step explanation:

good luck my friend

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A cafeteria manager needs to know how many apples and bananas to to order. He asked students to choose either an apple or a bana
Usimov [2.4K]

Answer:

Step-by-step explanation:

3/4 of total = 45

therefore, 1/4 took bananas

the ones taking bananas are 3 times less than those who took apples.

so we get 45/3 = 15 people picking bananas

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3 years ago
Hello can anyone help me with my algebra i'm behind
madreJ [45]

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Step-by-step explanation:

3 0
3 years ago
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco
kari74 [83]

Answer:

C. \frac{1}{18}

Step-by-step explanation:

Given: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5.

Solution:

Sample space for sum of cards when two cards are drawn at random is \{(1,1),(1,2),(1,3)......(6,6)\}

total number of possible cases =36

Sample space when sum of cards is 8 is \{(3,5),(5,3),(6,2),(2,6),(4,4)\}

Total number of possible cases =5

Sample space when one of the cards is 5 is \{(5,3),(3,5)\}

Total number of possible cases =2

Let A be the event that sum of cards is 8

p(\text{A}) =\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}

p(\text{A})=\frac{5}{36}

Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

p(\frac{\text{B}}{\text{A}})=\frac{2}{5}

Now,

probability that sum of cards 8 is and one of cards is 5

p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})

p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

if sum of cards is 8 then probability that one of the cards is 8 is \frac{1}{18}, option C is correct.

3 0
3 years ago
NEEED HELPPPP TRYING NOT TO FAIL MATHH !!
Oliga [24]
The answer is C hope it helped
3 0
2 years ago
The dimensions of the following matrix M are 2 x 3.<br><br><br><br> True<br> False
Lostsunrise [7]

Answer:

true, refer to picture for more understanding :)

3 0
3 years ago
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