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3 years ago

What is the surface area? 2 mm 2 mm 2 mm square millimeters

Mathematics

1 answer:

Alona [7]3 years ago

4 0

Answer:

24 mm^2

Step-by-step explanation:

length x width x 6 sides in a cube

(2)(2)(6)=24

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Write this number in standard form 2,000,000+80,000+1,000+300+3

Arte-miy333 [17]

Answer:

2,081,303

Step-by-step explanation:

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4 years ago

Read 2 more answers

III

Galina-37 [17]

Answer:

$9x- 60=10$

Step-by-step explanation:

Given

$\frac{3}{4}x - 5 = \frac{5}{6}$

Required

Rewrite to remove fractions

The denominators in the above expression are 4 and 6.

So, first we take the LCM of 4 and 6

$LCM = 12$

Next, multiply both sides of the equation by this LCM (12)

$12 ( \frac{3}{4}x - 5) = \frac{5}{6} * 12$

$12 * \frac{3}{4}x - 12 *5 = \frac{5}{6} * 12$

$3 * 3x- 60=5 * 2$

$9x- 60=10$

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3 years ago

Find x please help this is literally my final exam

hoa [83]

Answer is B

Step-by-step explanation:

You have the side opposite the angle and the Hypotenuse so use soh

Sine(x) = opposite/Hypotenuse

Sine(x) = 9/19

X = sin-1(9/19) - - - - - here the - 1 is to the power of

X= 28,27371363

X= 23,3

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3 years ago

Simplify 5n - 2n - 3 + n

Minchanka [31]

Answer:

that's your answer...

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3 years ago

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Write the equation in exponential form. Assume that all constants are positive and not equal to 1.

algol13

Answer:

1. $16 = 4^2$

2. $2 = {16}^{\frac{1}{4}}$

3. $log_2 y=z$

Step-by-step explanation:

$1.\ log_2 16=4$

Write in exponential form

Using the law of logarithm which says if

$log_b A=x$

then

$A = b^x$

By comparison;

A = 16; b = 2 and x = 4

The expression $log_2 16=4$ becomes

$16 = 4^2$

$2.\ log_{16} 2=\frac{1}{4}$

Write in exponential form

Applying the same law as used in (1) above;

A = 2; b = 16 and $x = \frac{1}{4}$

The expression $log_{16} 2=\frac{1}{4}$ becomes

$2 = {16}^{\frac{1}{4}}$

$3.\ 2^z=y$

Write in logarithm form

Using the law of logarithm which says if

$b^x =A$

then

$log_b A=x$

By comparison;

b = 2; x = z and A = y

The expression $2^z=y$ becomes

$log_2 y=z$

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3 years ago