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Ber [7]
2 years ago
5

What is the maximum number of elements that will be visited by the binary search algorithm when searching a sorted 45-element ar

ray
Computers and Technology
1 answer:
sergey [27]2 years ago
6 0

The max nukber of elements visited will be 6.

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Queues can be represented using linear arrays and have the variable REAR that point to the position from where insertions can be
Levart [38]

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8

Explanation:

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3 years ago
The basic difference between RAM and ROM memory is: Question 5 options: A) RAM is nonvolatile while ROM is volatile. B) RAM is r
schepotkina [342]

The basic difference between RAM and ROM memory is RAM is read/write while ROM Is read-only.

Explanation:

  • A ROM, non-volatile memory, does not use to store data, but RAM is volatile and requires power to store data.
  • ROM is not given usually as a specification, but RAM is typically specified when buying a computer.
  • We can write data only once in ROM. However, once it is written, we can read it any number of times. RAM is the main memory in a computer, and read from and write to it much faster than other storage types. RAM is used to store files in use on the computer.

Hence the basic difference between RAM and ROM memory is RAM is read/write while ROM Is read-only.

6 0
3 years ago
WHO SAYS BUP ALL THE TIME ​
Delvig [45]

Answer:

Mario

Explanation:

7 0
3 years ago
Write a RainFall class that stores the total rainfall for each of 12 months into an array of doubles. The program should have me
RSB [31]

Answer:

Explanation:

The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.

import java.io.*;

import java.util.*;

class Rainfall

{

   Scanner in = new Scanner(System.in);

   private int month = 12;

   private double total = 0;

   private double average;

   private double standard_deviation;

   private double largest;

   private double smallest;

   private double months[];

   public Rainfall()

   {

       months = new double[12];

   }

   public void setMonths()

   {

       for(int n=1; n <= month; n++)

       {

           int answer = 0;

           while (true) {

               System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );

               answer = in.nextInt();

               if (answer > 0) {

                   months[n-1] = answer;

                   break;

               }

           }

       }

   }

   public void getTotal()

   {

       total = 0;

       for(int i = 0; i < 12; i++)

       {

           total = total + months[i];

       }

       System.out.println("The total rainfall for the year is " + total);

   }

   public void getAverage()

   {

       average = total/12;

       System.out.println("The average monthly rainfall is " + average);

   }

   public void getLargest()

   {

       double largest = 0;

       int largeind = 0;

       for(int i = 0; i < 12; i++)

       {

           if (months[i] > largest)

           {

               largest = months[i];

               largeind = i;

           }

       }

       System.out.println("The largest amount of rainfall was " + largest +

               " inches in month " + (largeind + 1));

   }

   public void getSmallest()

   {

       double smallest = Double.MAX_VALUE;

       int smallind = 0;

       for(int n = 0; n < month; n++)

       {

           if (months[n] < smallest)

           {

               smallest = months[n];

               smallind = n;

           }

       }

       System.out.println("The smallest amount of rainfall was " + smallest +

               " inches in month " + (smallind + 1));

   }

   public static void main(String[] args)

   {

       Rainfall r = new Rainfall();

       r.setMonths();

       r.getTotal();

       r.getSmallest();

       r.getLargest();

       r.getAverage();

   }

}

8 0
3 years ago
Decrypt this secret message if your able to a lot will come..
nata0808 [166]

Answer:-

Failure

and 0008

Hope This Helps

7 0
3 years ago
Read 2 more answers
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