F(x)=x² +6 Find an equation for the tangent line to the graph of f(x) = x² +6 at (5,31). y=

Mathematics

1 answer:

olganol [36]1 year ago

8 0

Answer:

y = x^2 + 6 given equation

y = m x + b equation of straight line required

dy/dx = 2 x tangent to given curve

dy/dx = slope = 2 * 5 = 10

Thus our line must be of the form

y = 10 x + b

31 = 10 * 5 + b at the point required

b = 31 - 50 = -19

Then our final equation becomes

y = 10 x - 19

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