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Vikki [24]
3 years ago
9

Select the correct answer.

Mathematics
1 answer:
raketka [301]3 years ago
6 0

The range of the function shown on the graph below is equal to 0 ≤ y ≤ 7.

<h3>What is a range?</h3>

A range refers to the set of all real numbers that connects with the elements of a domain. This ultimately implies that, a range is the solution set on the y-axis.

<h3>How to determine the range?</h3>

Based on the graph of the two points, we can logically deduce the following information:

  • The least value on the y-axis is 0.
  • The greatest value on the y-axis is 7.
  • The endpoints on the y-axis are 0 and 7.

Therefore, the range of the function shown on the graph below is equal to 0 ≤ y ≤ 7.

Read more on range here: brainly.com/question/16610662

#SPJ1

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In 2008, there were 507 children in Arizona out of 32,601 who were diagnosed with Autism Spectrum Disorder (ASD) ("Autism and de
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Answer:

z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318    

p_v =P(Z>0.318)=0.375  

So the p value is a very high value and using the significance level provided \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

Step-by-step explanation:

Data given and notation  

X_{1}=507 represent the number of children diagnosed with Autism Spectrum Disorder (ASD) in Arizona

n_{1}=32601 sample elected from arizona

\hat p_{1}=\frac{507}{32601} =0.0156 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona

p_{2}=\frac{1}{88}= 0.0114 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD)  in the nation

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if that the incident of ASD is more in Arizona than nationally, the system of hypothesis are:

Null hypothesis:p_{1} \leq p_{2}  

Alternative hypothesis:p_{1} > p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{507+1}{32601 +88}=0.01554  

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318    

Statistical decision

The significance level provided is \alpha=0.01, and we can calculate the p value for this test.    

Since is a one right sided test the p value would be:  

p_v =P(Z>0.318)=0.375  

So the p value is a very high value and using the significance level provided \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

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