The expression is:
(z^2 - 4)
_______
z - 3
_______________
z + 2
___________
z^2 + z - 12
You can factor the numerator z^2 - 4 = (z + 2) (z - 2)
And the denominatior z^2 + z + 12 = (z + 4)(z - 3)
That permits to write the quotient as:
(z + 2)(z - 2)
___________
z - 3
_______________
z + 2
___________
(z + 4)(z - 3)
Now you can multiplicate the numerator of the numerator times the denominator of the denominator, and multtiplicate the denominator of the numerator times the numerator of the denominator to obtain:
(z + 2)(z - 2)(z + 4)(z - 3)
____________________
(z - 3)((z + 2)
Cancel the factors (z - 3) and (z + 2) because they are in both the numerator and the denominator =>
(z - 2)(z + 4) = z^2 + 2z - 8
The restrictions are that none of the cancelled factors can be 0, so z ≠ 3 and z ≠- 4.
Answer: 2+2=4 / 100-40=60
Step-by-step explanation:
3/4 = x / 340....3 to 4 students = x to 340 students
cross multiply
(4)(x) = (3)(340)
4x = 1020
x = 1020/4
x = 255 <==
or this way.....
3 out of 4 students.....3/4 = 75%
so 75% of 340 = 0.75(340) = 255 <=