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Stels [109]
3 years ago
5

Can someone help me write the equations and solve, please.

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

Number 11: She has to add 5/36 of a cup

Number 12: The present costs $22,2

Number 13: 56,7 pounds is the weight of the package.

Number 14: You started with 40 muffins

Step-by-step explanation:

<u>Number 11</u>: 1/4 = 9/36  and 1/9 = 4/36

3*1/4  -  3*1/9  = 3*9/36  - 3*4/36  = 5/36

<u>Number 12:</u> 13,32/x= 3/5 ( or 0,6)

x = 13,32/0,6 = 22,2

<u>Number 13:</u> x * 5/7 = 40,5

x = 40,5/ (5/7) or 40,5 * 7/5 = 283,5/5 = 56,7

<u>Number 14:</u> 12/x = 3/10 (or 0,30)

x= 12/0,30 = 40

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Answer as an inequality:  x > 0

Answer in interval notation:  (0, \infty)

Answer in words: Set of positive real numbers

All three represent the same idea, but in different forms.

======================================================

Explanation:

Any log is the inverse of an exponential equation. Consider a general base b such that f(x) = b^x. The inverse of this is f^{-1}(x) = \log_b(x)

For the exponential b^x, we cannot have b^x = 0. We can get closer to it, but we can't actually get there. The horizontal asymptote is y = 0.

Because of this, \log_b(x) has a vertical asymptote x = 0 (recall that x and y swap, so the asymptotes swap as well). This means we can get closer and closer to x = 0 from the positive side, but never reach x = 0 itself.

The domain of \log_b(x) is x > 0 which in interval notation would be (0, \infty). This is the interval from 0 to infinity, excluding both endpoints.

------------------------

The natural log function Ln(x) is a special type of log function where the base is b = e = 2.718 approximately.

So,

\log_e(x) = \text{Ln}(x)

allowing all of what was discussed in the previous section to apply to this Ln(x) function as well.

------------------------

In short, the domain is the set of positive real numbers. We can't have x be 0 or negative.

8 0
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