Answer:
<h2>
√34sin(x + 0.33π)</h2>
Step-by-step explanation:
The general form of the equation acosx + bsinx = Rsin(x + e) where R is the resultant of the constants 'a' and 'b' and e is the angle between them.
R = √a²+b²
Given the function f(x) = 3 cos x + 5 sin x, comparing with the general equation;
a = 3, b = 5
R = √3²+5²
R = √9+25
R =√34
in radians;
3 cos x + 5 sin x = √34sin(x + 0.33π)
Step-by-step explanation:
if b+c=0
b=-c
x^b=x^-c
so
1/[2(x^b)+1]
Make all a and constant number in different side
10-7=16z-7z+2z
3=11z
z=3/11
I think it will be (6v-1) because its the opposite.