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Nonamiya [84]
2 years ago
6

Lanetterisbelle

Mathematics
1 answer:
Ierofanga [76]2 years ago
5 0

Each transaction has been an analyzed in the trial balance below by showing its effects on the accounting equation-specifically, identifying the accounts and amounts.

<h3>How to prepare a Trial Balance?</h3>

The Journal Entries are:

Cash                                                                                 6500

Photography equipment                                                33500

                  Capital                                                                       40000

Prepaid Insurance                                                           2100

                   Cash                                                                         2100

Office Supplies                                                                  880

                  Cash                                                                          880

Cash                                                                                   3331

           Revenue                                                                          3331

Utilities Expense                                                                 675

           Cash                                                                                 675

Cash account = 6500 - 2100 - 880 + 3331 - 675

Cash Account = 6176

                                                     Trial Balance

                                                                              Debit                         Credit

Cash                                                                       6176

Prepaid Insurance                                                  2100

Supplies                                                                   880

Revenue                                                                                                      3331

Utilities Expense                                                      675

Capital                                                                                                       40000

Photography Equipment                                         33500

Total                                                                         43331                       43331

Read more about Trial Balance at; brainly.com/question/24914390

#SPJ1

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Can someone please help super short
insens350 [35]

Answer:

542, 543, 544, 545.

Step-by-step explanation:

Divide 2174 by 4 = 543.5  

(because there are 4 integers) 543.5 is not an integer.

However, one of the four integers is 543.

Write down four consecutive numbers that include 543 and add them:  

like 541+542+543+544 =. if that is 2174, you have the answer, if it's too low, try moving up one number, like

542+543+544+545 = if it's still too low, move up one number again  

543+544+545+546=  

You only have to do that a max of 3 times to get the answer.

The four consecutive integers are  

542, 543, 544, 545.

<em>good luck, hope this helps :)</em>

3 0
3 years ago
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A farmer has a field in the shape of a semicircle of diameter 50 m. First,
dexar [7]

Answer:

157.1 m

Step-by-step explanation:

Here, we want to calculate the length of the semi-circle

This simply refers to the circumference of the semi-circle

Mathematically, the circumference is half that of a full circle

The circumference of a full circle is;

C = pi * d

For half circle or semi-circle;

It is ;

C = (pi * d)/2

D = 50 m

The circumference is thus;

C = 50 * 3.142

C = 157.1 m

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Which expression can be used to find the volume of the sphere? 10 in. ​
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Step-by-step explanation:

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Suppose that W1, W2, and W3 are independent uniform random variables with the following distributions: Wi ~ Uni(0,10*i). What is
nadya68 [22]

I'll leave the computation via R to you. The W_i are distributed uniformly on the intervals [0,10i], so that

f_{W_i}(w)=\begin{cases}\dfrac1{10i}&\text{for }0\le w\le10i\\\\0&\text{otherwise}\end{cases}

each with mean/expectation

E[W_i]=\displaystyle\int_{-\infty}^\infty wf_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac w{10i}\,\mathrm dw=5i

and variance

\mathrm{Var}[W_i]=E[(W_i-E[W_i])^2]=E[{W_i}^2]-E[W_i]^2

We have

E[{W_i}^2]=\displaystyle\int_{-\infty}^\infty w^2f_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac{w^2}{10i}\,\mathrm dw=\frac{100i^2}3

so that

\mathrm{Var}[W_i]=\dfrac{25i^2}3

Now,

E[W_1+W_2+W_3]=E[W_1]+E[W_2]+E[W_3]=5+10+15=30

and

\mathrm{Var}[W_1+W_2+W_3]=E\left[\big((W_1+W_2+W_3)-E[W_1+W_2+W_3]\big)^2\right]

\mathrm{Var}[W_1+W_2+W_3]=E[(W_1+W_2+W_3)^2]-E[W_1+W_2+W_3]^2

We have

(W_1+W_2+W_3)^2={W_1}^2+{W_2}^2+{W_3}^2+2(W_1W_2+W_1W_3+W_2W_3)

E[(W_1+W_2+W_3)^2]

=E[{W_1}^2]+E[{W_2}^2]+E[{W_3}^2]+2(E[W_1]E[W_2]+E[W_1]E[W_3]+E[W_2]E[W_3])

because W_i and W_j are independent when i\neq j, and so

E[(W_1+W_2+W_3)^2]=\dfrac{100}3+\dfrac{400}3+300+2(50+75+150)=\dfrac{3050}3

giving a variance of

\mathrm{Var}[W_1+W_2+W_3]=\dfrac{3050}3-30^2=\dfrac{350}3

and so the standard deviation is \sqrt{\dfrac{350}3}\approx\boxed{116.67}

# # #

A faster way, assuming you know the variance of a linear combination of independent random variables, is to compute

\mathrm{Var}[W_1+W_2+W_3]

=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]+2(\mathrm{Cov}[W_1,W_2]+\mathrm{Cov}[W_1,W_3]+\mathrm{Cov}[W_2,W_3])

and since the W_i are independent, each covariance is 0. Then

\mathrm{Var}[W_1+W_2+W_3]=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]

\mathrm{Var}[W_1+W_2+W_3]=\dfrac{25}3+\dfrac{100}3+75=\dfrac{350}3

and take the square root to get the standard deviation.

8 0
3 years ago
7(2x+5) = 11x-9-x <br><br> Please HELP
mr_godi [17]

Step-by-step explanation:

7(2x+5)=11x-9-x

14x+35=10x-9

4x+35=-9

4x=-44

x=-11

3 0
3 years ago
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