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Marina CMI [18]
3 years ago
15

About to cry. extra points given!!!

Mathematics
1 answer:
enot [183]3 years ago
5 0

Answer:

try dividing the dividend and then multiplying it by the center number

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Help urgent plz!❤️❤️❤️Please please urgently
sleet_krkn [62]

Answer:

Problem 2): \left \{x\, |\,0\leq x\leq 240\,\,\right \}

which agrees with answer C listed.

Problem 3) :  D = (-3, 6]  and R = [-5, 7]

which agrees with answer D listed

Step-by-step explanation:

Problem 2)

The Domain is the set of real numbers in which the function (given by a graph in this case) is defined. We see from the graph that the line is defined for all x values between 0 and 240. Such set, expressed in "set builder notation" is:

\left \{x\, |\,0\leq x\leq 240\,\right \}

Problem 3)

notice that the function contains information on the end points to specify which end-point should be included and which one should not. The one on the left (for x = -3 is an open dot, indicating that it should not be included in the function's definition, therefor the Domain starts at values of x strictly larger than -3. So we use the "parenthesis" delimiter in the interval notation for this end-point. On the other hand, the end point on the right is a solid dot, indicating that it should be included in the function's definition, then we use the "square bracket notation for that end-point when writing the Domain set in interval notation:

Domain = (-3, 6]

For the Range (the set of all those y-values connected to points in the Domain) we use the interval notation form:

Range = [-5, 7]

since there minimum y-value observed for the function is at -5 , and the maximum is at 7, with a continuum in between.

6 0
3 years ago
Is my answer right?? if not which one is it?? BRAINLIEST IF UR CORRECT!
lorasvet [3.4K]

Answer:

Step-by-step explanation:

1 yes

2 yes

3 yes

4 yes

6 0
3 years ago
Two ways to solve 2(4x-11)=10
Leokris [45]
Hi there,

2 (4x - 11) = 10
4x - 11 = 5
4x = 5 + 11
4x = 16 then divide both sides by 4
16 divided by 4 = 4

Hope this helps :)
3 0
3 years ago
The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th
ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}

By doing so, we find:

|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1

4 0
3 years ago
Show that sinxtanx=1-cos^2x/cosx
yawa3891 [41]
LHS: = \sin x \tan x =  \frac{\sin x \sin x }{\cos x} =  \frac{\sin^2 x}{\cos x} (using \tan x =  \frac{\sin x}{\cos x})

We know \sin^2x + \cos^2x = 1 \Rightarrow \sin^2x=1-\cos^2x so we can replace the sin²x in the LHS expression as follows

\frac{\sin^2x}{\cos x} =  \frac{1-\cos^2x}{\cos x} which is the RHS.
7 0
3 years ago
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