The answer to that question is (5x+3).
V = (pi)r² h
v = (pi)5² h
v = 25(pi) h
take derivative with respect to h
dv/dh = 25(pi)
(dv/dt)*(dt/dh) = dv/dh
dv/dt is given to be 5 cm³
solved for dv/dh = 25(pi)
5(dt/dh) = 25(pi)
dt/dh = 25(pi)/5
dt/dh = 5(pi)
then the recipricol of dt/dh; we want to find dh/dt = 1/(5(pi))
The expression D=23g shows the distance that Kurt can drive on a tank of gasoline.
Step-by-step explanation:
Given,
Distance covered by Kurt's car = 23 miles per gallon of gasoline
Kurt fills up tank of his car with g gallons.
Number of gallons in car's tank = g gallons
Distance covered by g gallons = D = Distance covered by one gallon * Number of gallons
D = 23*g
D = 23g
The expression D=23g shows the distance that Kurt can drive on a tank of gasoline.
Keywords: distance, multiplication
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your answer would be that the sematry would be vertical semmetry