Since these are supplementary angles (two angles which sum to 180°) we can say:
4x+x=180 combine like terms on left side
5x=180 divide both sides by 5
x=36°
Answer:
Marie Skłodowska Curie (born Maria Salomea Skłodowska (Polish: [ 7 November 1867 – 4 July 1934), was a Polish and naturalized-French physicist and chemist who conducted pioneering research on radioactivity. As the first of the Curie family legacy of five Nobel Prizes, she was the first woman to win a Nobel Prize, the first and the only woman to win the Nobel Prize twice, and the only person to win the Nobel Prize in two scientific fields. She was the first woman to become a professor at the University of Paris in 1906.[4]
Step-by-step explanation:
Answer:
a) 1 / 12
b) 1 / 4
Step-by-step explanation:
The events are independent since they do not affect each other. The total probability of two independent events is the product of the probabilities of the two events.
a) When rolling a die, there are 6 outcomes, the numbers 1 - 6. There is only 1 outcome where you can get a 2. Therefore, the probability of rolling a two is 1/6.
When flipping a coin, there are two ways it can land: heads or tails. And there is one outcome with heads. The probability of getting head would be 1 / 2.
To find the the total, you multiply the probabilities of the two events: 1 / 6 * 1 / 2 = 1 / 12
b) As stated before, when rolling a die, there are 6 outcomes, the numbers 1 - 6. There are 3 outcomes where she can roll an even number: the numbers 2, 4, or 6. So, the probability of rolling an even number is 3 / 6 or 1 / 2.
When flipping a coin, there are two ways it can land: heads or tails. And there is one outcome with tails. The probability of getting tails would be 1 / 2.
Now, you multiply the two probabilities to get the total probability: 1 / 2 * 1 / 2 = 1 / 4
Answer:
250 m
Step-by-step explanation:
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
