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ExtremeBDS [4]
4 years ago
14

2 fraction bars. The first bar is labeled 1 with 8 boxes underneath that are labeled one-eighth. The second bar is labeled 1 wit

h 8 boxes underneath that are labeled one-eighth. Use the drop-down menu to complete the statement. To find the quotient of 2 ÷ 3 8 , circle groups of ------
Mathematics
2 answers:
GaryK [48]4 years ago
8 0

Answer:

Sorry for the late reply but the answer is 3/8

Step-by-step explanation:

Just trust me i took it on edge

AlekseyPX4 years ago
7 0

Answer:

the answer is 1/3

hope this helps :)

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Please help tytytyty
masya89 [10]

Answer:

-24

Step-by-step explanation:

a= -3 b= 8 c=-4

This means 2 (-4 ^2) + 5 * 8 / -3

2 (-4 ^2) = 2 (16)

2 (16) = 32

Then:

5 * 8 = 40

this means 32 + 40 = 72

There after 72 divided by -3 is equal to -24.

HOPE THIS HELPED

8 0
3 years ago
Read 2 more answers
if 192 students voted and a quarter of them voted for turkey burgers how many voted for turkey burgers​
Lilit [14]

Answer:

48 students

Step-by-step explanation:

Since you need to know how many is a quarter of 192, and  a quarter equals 4 parts, you can divide 192 by 4 to get your answer, 48.

3 0
3 years ago
The value of -7 + 24 = (-3)(2) is<br> -23<br> -11<br> 23<br> 11
Helen [10]

Answer:

-11

Step-by-step explanation:

7 0
3 years ago
WILL GIVE YOU BRAIN IF YOU HELP WITH 8TH GRADE MATH PLEASEE<br>​
QveST [7]

Answer:

answer the branliest

Step-by-step explanation:

8 0
3 years ago
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What is the solution set to the inequality 5(x - 2)(x + 4) &gt; 0?
Butoxors [25]

Answer:

You selected the correct answer: {x | x <<em> </em>-4 or x > 2}

Step-by-step explanation:

5(x - 2)(x + 4) > 0

Use FOIL method to expand (x - 2)(x + 4):

5(x^{2} + 2x - 8) > 0

Distribute 5 into (x^{2} + 2x - 8)

5x^{2} + 10x - 40 > 0

Divide all terms by 5 from both sides of the inequality:

\frac{5x^{2}}{5}  + \frac{10x}{5}  - \frac{40}{5} > \frac{0}{5}

x^{2} + 2x - 8 > 0

Factor the trinomial:

(x + 4) ( x - 2)  > 0

x < -4 or x > -2

Therefore, the solution set to the inequality is {x | x < -4 or x > 2}

<em>Interval notation:  </em>(-∞, -4) ∪ (2, ∞)

8 0
3 years ago
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