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2 years ago

In the given figure BC || AD find the measure of angle x angle y and angle z

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

5 0

what is the picture?

put the pucture or write the name of the picture

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ella [17]

Answer:

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7 0

2 years ago

One sixth of forty-two is seven.<br> How do I write out the equation for that?

sertanlavr [38]

Answer:

Step-by-step explanation:

1/6 * 42 = 7

"of" means multiply

"is" means =

6 0

2 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

2 years ago

Solve the system of equations. x+2y=6; 3x-14y=8 please help

ira [324]

Let x = 6 = 2y so
3(6 - 2y) + 14y = 8 so
18 - 6y + 14y = 8 so
8y = -10 and
$y = \frac{ - 10}{8} = - \frac{5}{4} \\ \\ since \: x = 6 - 2y \\ 6 - 2( \frac{ - 5}{4}) = x \: so \\ x = 6 + \frac{10}{4} = \frac{24}{4} + \frac{10}{4} = \frac{34}{4} = \frac{17}{2}$

8 0

2 years ago

What is the greatest common factor of 6d² and 18d<br><br>

VMariaS [17]

gcd = 6 ⋅ d

Step-by-step explanation:

We have that

6 d ^2 = 6 ⋅ d ⋅ d and 18 d = 3 ⋅ 6 ⋅ d hence the gcd = 6 ⋅ d

(Hope this helps <3)

3 0

2 years ago