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Alex777 [14]
1 year ago
15

Which option below demonstrates the correct interval notation for a

Mathematics
1 answer:
Vladimir [108]1 year ago
3 0

The correct interval notation for the continuous set of all numbers between 5 and 6, including 5, but not including 6 is [5, 6) option (C) is correct.

<h3>What is interval notation?</h3>

It is defined as the representation of a set of values that satisfy a relation or a function. It can be represented as open brackets and close bracket the close the brackets means the value is at the close bracket also included, and open bracket means the value at the open bracket does not include.

We have:

Continuous set of all numbers between 5 and 6, including 5, but not including 6.

From the above statement we can represent the number in the interval notation:

The numbers are between 5 and 6.

(5, 6)

As it is mentioned that 5 is included and 6 is not included, then:

[5, 6)

Thus, the correct interval notation for the continuous set of all numbers between 5 and 6, including 5, but not including 6 is [5, 6) option (C) is correct.

Learn more about the interval notation here:

brainly.com/question/13048073

#SPJ1

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Students are voting for a Friday Funday activity. 0.84 want a movie and snack. There are 300 voters. How many votes does the win
erastova [34]

Answer:

Step-by-step explanation:

0.84(300)=252

3 0
2 years ago
Order the measurements from largest to smallest.<br> 4.9L , 4090ml , 1.4km , 4901m
Burka [1]

Answer:

4090 ml - 4.9L

1.4km - 4901m

Step-by-step explanation:

A liter is made up of 1000 ml so 4.9 l is equvilant to 4,900 ml.

A kilometre same as litre is made up of a 1000 m. So 1.4 km is 1400m

However, ml and l is a measurement of volume while m and km is a measurement of distance.

6 0
3 years ago
If I had a 2% solution, added 2 ounces to a gallon (128 ounces) What is the final concentration of the solution.
Ne4ueva [31]
<span>A 2% solution of chlorohexidine added to 126 oz of water. The total oz 128.

Solute: chlorohexidine, 2%=0.02
solvent: water (0%)

Concentration, C, volume V
CV=c1v1+c2v1
128C=0.02*2 + 0.00*126 = 0.04

Concentration
C=0.04/128 = 0.0003125 = 0.03125%</span>
6 0
3 years ago
6th grade help please
miv72 [106K]
12 + 6x + 6x + 6y = 12 + 12x + 6y
8 0
2 years ago
Read 2 more answers
A path 2.5m wide is running outside a square field whose side is 45m. Determine the area of the path.
aliya0001 [1]

Answer:

The area of the path would be 231.25 squared meters.

Step-by-step explanation:

Consider the path as 45m (the field's area), then add 2.5m to all of the sides. You'll get 47.5m on all sides. Then you do 47.5² to get 2256.25 squared meters. After that, you'll remove the area of the squared field. To do this, do 45m². By doing this, you'll get 2025 squared meters. Lastly, to finish up the question, do 2256.25 - 2025. This would get you 31.25 squared meters, the answer.

4 0
3 years ago
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