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4 years ago

Fins the product of (3s+2t)(3s-3t)

Mathematics

2 answers:

erastovalidia [21]4 years ago

6 0

Your answer is 9s^2-9st+6st-6t^2

Mamont248 [21]4 years ago

4 0

Do the FOIL method. (F)irst, (O)uter, (I)nner, (Last, In Which you multiply the first set of number and variables in each set, (3s times 3s), the outer set of number and variable in each set, (3s times negative 3t, the inner number and variable in each set,(2t times 3s), and the last ones, (2t times negative 3t).

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Find the period. Principal = 9300 =9300equals, 9300 rupees Annual rate of interest = 13 % =13%equals, 13, percent Total amount =

tekilochka [14]

Answer:

7 years

Step-by-step explanation:

Given:

Principal P = 9300

Interest rate r = 13% = 0.13

Final amount F = 17,763

Since the problem does not state that it is a compounded interest, we will assume this is a simple interest case.

The formula for simple interest is;

Interest I = Prt .....1

t = period

Final amount F = P + I

I = F-P

Substituting into equation 1;

(F-P) = Prt

t = (F-P)/Pr

Substituting the given values;

t = (17,763 - 9300)/(9300×0.13)

t = 7 years

Period = 7 years

5 0

4 years ago

Please Answer ASAP According to the table, which ordered pair is a local maximum of the function, f(x)? (0, 64) (3, –35) (5, 189

Katarina [22]

The ordered pair that represents a maximum is (5,189)

6 0

3 years ago

Do u know rulers take 2# I already ask this question its just take I put the wrong file

vesna_86 [32]

Answer:

9 and a half inches

Step-by-step explanation:

Just count via the ruler!

3 0

3 years ago

Read 2 more answers

Help what is the value of X

EastWind [94]

I hope this helps. Since there are verticale angles that’s why I added another x.

5 0

3 years ago

A researcher tests five individuals who have seen paid political ads about a particular issue. These individuals take a multiple

devlian [24]

Answer:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

Step-by-step explanation:

Information given

48, 41, 40, 51, and 50

The sample mean and deviation can be calculated with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=46$ represent the mean height for the sample

$s=5.148$ represent the sample standard deviation

$n=5$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis to test

We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:

Null hypothesis: $\mu = 40$

Alternative hypothesis: $\mu \neq 40$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

6 0

4 years ago