Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box
we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1
surface area of the box=area of the base+perimeter of base*height
area of the base=b²
perimeter of the base=4*b
surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2
substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b
the answer is
the formula of the volume of the box is V=b²*h-----> 256=b²*h
the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
Answer:
3
Step-by-step explanation:
distance formula
Answer:
Step-by-step explanation:
First you need to do 5x5=25
A
The domain is -∞ < x < ∞
B
The range is -∞ < x ≤ 3
C
The graph is increasing from -∞ < y < 3
D
The graph is decreasing from 3 > y > -∞
E
The local maximum is at ( - 2, 3 )
F
There are no local minimums
