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2 years ago

Question 5 of 10

Mathematics

2 answers:

Mrrafil [7]2 years ago

8 0

Answer:

S=6a^2

S=6×2^2

S=6×4=24

The right answer is C

nasty-shy [4]2 years ago

4 0

Answer:

24 units²

Explanation:

The surface area of cube is 6(side)²

Here given:

a = 2

The surface area:

= 6(2)^2

= 6(4)

= 24

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Alice says that all the factors of 8 are even.

Rom4ik [11]

1 is not even yet it is a factor of 8. Alice is wrong.

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2 years ago

Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!

kupik [55]

Answer:

The equation of required line is: $\mathbf{5x-8y+34=0}$

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to $5x-8y+12=0$ and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line $5x-8y+12=0$ to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: $y=mx+b$ where m is slope.

$5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}$

So, the slope m = 5/8

The slope of required line is $m=\frac{5}{8}$

Now finding y-intercept using slope $m=\frac{5}{8}$ and point(-2,3)

$y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}$

So, the equation of required line having slope $m=\frac{5}{8}$ and y-intercept $b=\frac{17}{4}$

$y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8} \\8y=5x+34\\5x-8y+34=0$

So, The equation of required line is: $\mathbf{5x-8y+34=0}$

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2 years ago

Tyre measured the average monthly temperature in degrees Fahrenheit for several months. If February is set ect 2 and June is oud

Katena32 [7]

Answer:

it will be d

Step-by-step explanation:

7 0

2 years ago

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Find the missing dimension of the prism. Round your answer to the nearest hundredth.

Nitella [24]

Answer:

$x = 6.99in$

Step-by-step explanation:

Given

$l =2in$

$Volume = 72.66in^3$

See attachment for prism

Required

Find x

The prism has a regular hexagon base

The base area is calculated as:

$Base\ Area= \frac{3\sqrt 3}{2}l^2$

This gives:

$Base\ Area= \frac{3\sqrt 3}{2} * 2^2$

$Base\ Area= \frac{3\sqrt 3}{2} * 4$

$Base\ Area= 3\sqrt 3 * 2$

$Base\ Area= 6\sqrt 3$

Side x represents the height.

So, we have:

$Volume = Base\ Area*x$

Make x the subject

$x = \frac{Volume }{ Base\ Area}$

$x = \frac{72.66in^3}{6\sqrt 3 in^2}$

$x = \frac{72.66}{6\sqrt 3}in$

$x = \frac{12.11}{\sqrt 3}in$

$x = 6.99in$ --- approximated

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3 years ago

What is 7 + 8(2r - 9)

Shalnov [3]

7 + 8(2r - 9)

mutiply the bracket by 8

(8)(2r)= 16r

(8)(-9)= -72

7+16r-72

7-72+16r ( rearranging)

answer:

-65+16r or 16r-65

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3 years ago

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