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1 year ago

Factor the Expression completely -16x^2-6x^4

Mathematics

1 answer:

denpristay [2]1 year ago

7 0

Answer: -2x^2 (3x^2 + 8)

Step-by-step explanation: a^b+c =a^b a^c

1) -16x^2 - 6x^ x^2

2) Rewrite -16 as -2 * 8

2.a Rewrite -6 as -2 * 3

= -2 * 8x^2 - 2 * 3x^2x^2

3) facter out common term: -2x^2

= ur answer

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Step-by-step explanation:

Here, the given expression is : $M(a) = -\frac{3}{4} a-12$

Here, let M(a) = b

⇒The equation becomes $b = -\frac{3}{4} a-12$

Now, check for all the given points for (a,b)

1) FOR (-9,0)

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Hence, (-9,0) is NOT on the graph.

2) FOR (-16,0)

Here, LHS = b = 0

and $RHS = -\frac{3}{4} (-16)-12 = 12-12 = 0$

Hence, LHS = RHS = 0 So, (-16,0) is on the graph.

3) FOR (0,12)

Here, LHS = b = 12

$RHS is -\frac{3}{4} (0)-12 = -12 \neq 12$

Hence, (0,12) is NOT on the graph.

4) FOR (0,-12)

Here, LHS = b = -12

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Hence, (0,-12) is on the graph.

Hence, (-16, 0) and (0,-12) are exactly two points on the graph of the given equation.

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