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Art [367]
3 years ago
9

What is the slope of points (-3,-3) and (4,5)?

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0
The slope is 2. y2-y1/x2-x1
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Three consecutive integers have a sum of 75. Find the integers
natima [27]
The answers is 24, 25, and 26.
8 0
2 years ago
Read 2 more answers
Tangent please help me
atroni [7]
A^2+ b^2= c^2
24^2+b^2=25^2
576+b^2=625
Sub 576
b^2= 49 b=7
6 0
2 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
The 11 foot long bed of a dump truck loaded with debris must rise an angle of degrees before the debris will spill out. Approxim
Ymorist [56]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete. The complete question is:

The 12 foot long bed of a dump truck loaded with debris must rise an angle of 30 degrees before the debris will spill out. Approximately how high must the front of the bed rise for the debris to spill out.

Solution:

Let x be the height of the front of the bed rise needed to be raised for the debris to spill out. We can find x using trigonometric identities. That is:

sin θ = opposite / hypotenuse

Using trigonometric identities, we can get that:

sin(30) = x / 12

This gives:

0.5 = x / 12

Cross multiplying the terms to get:

x = 12 * 0.5

x = 6 ft

Therefore the front of the bed rise must be raised 6 ft for the debris to spill out.

4 0
3 years ago
Jenna has a piece of paper that is 84 square inches in area. It is 21/2 inches long. What is the length of the piece of paper in
Lerok [7]

Answer:

Step-by-step explanation:

Area = 84sqaure inch

Width = 2 1/2inch = 5/2inch

Area = l × width

So: 84 = l × 5/2

168 = 5l

l =>168/5

l = 33 3/5

7 0
3 years ago
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