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maw [93]
1 year ago
12

Construct three parallel lines. Then construct two arbitrary non parallel transversal of the parallel lines. Make sure that the

transversals cut the three parallel lines at distinct points mark the points of intersection where the transversals cut the parallel lines. Take a screenshot of your construction, save it, and insert the image below.

Mathematics
1 answer:
zzz [600]1 year ago
7 0

The image lines constructed are called parallel lines. They are parallel because  they are all equidistant to each other at every point and at no point between any of the lines will there be an intersection of the three lines.

<h3>What does it mean for two or more lines to be equidistant from each other?</h3>

Equidistance is simply another word for equal in distance. That is, parallel lines maintain equal distance from each other at all points along them.

See the attached construction as well as more insights about parallel lines from the link below.

brainly.com/question/24607467'

#SPJ1


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148 ÷ 10 = 14.8

$14.80 is the median amount the ten friends had to pay.
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Is it written like this?

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14girls to 35boys how does this go into a fraction
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Step-by-step explanation:

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If Angle B is two more than three times the measure of Angle C, and Angle B and Angle C are complementary angles, find each angl
dolphi86 [110]

Answer:

The measure of angle B is 68° and the measure of angle C is 22°

Step-by-step explanation:

we know that

If two angles are complementary, then their sum is equal to 90 degrees

m∠B+m∠C=90° -----> equation A

m∠B=3(m∠C)+2 ----> equation B

Substitute equation B in equation A and solve for m∠C

3(m∠C)+2+m∠C=90

4(m∠C)=90-2

4(m∠C)=88

m∠C=88/4

m∠C=22°

Find the value of m∠B

m∠B=3(22)+2=68°

therefore

The measure of angle B is 68° and the measure of angle C is 22°

5 0
2 years ago
What are the solutions to the equation?<br> 7x^3=28x
11Alexandr11 [23.1K]

7x³ = 28x is our equation. We want its solutions.

When you have x and different powers, set the whole thing equal to zero.

7x³ = 28x

7x³ - 28x = 0

Now notice there's a common x in both terms. Let's factor it out.

x (7x² - 28) = 0

As 7 is a factor of 7 and 28, it too can be factored out.

x (7) (x² - 4) = 0

We can further factor x² - 4. We want a pair of numbers that multiply to 4 and whose sum is zero. The pairs are 1 and 4, 2 and 2. If we add 2 and -2 we get zero.

x (7) (x - 2) (x + 2) = 0

Now we use the Zero Product Property - if some product multiplies to zero, so do its pieces.

x = 0        -----> so x = 0

7 = 0       -----> no solution

x - 2 = 0   ----> so x = 2   after adding 2 to both sides

x + 2 = 0  ---> so = x - 2  after subtracting 2 to both sides


Thus the solutions are x = 0, x = 2, x = -2.

6 0
2 years ago
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