Answer:
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Step-by-step explanation:
Answer:
Yes, he is meeting his original goal to be successful.
The critical value is 1.833
Step-by-step explanation:
H0: mu = 300
Ha: mu > 300
The test is a one-tailed test because the alternate hypothesis is expressed using greater than.
Test statistic (t) = (sample mean - population mean) ÷ (sample sd/√n)
sample mean = 335
population mean = 300
sample sd = 50
n = 2×5 = 10
t = (335 - 300) ÷ (50/√10) = 35 ÷ 15.81 = 2.21
Degree of freedom = n-1 = 10-1 = 9
Significance level = 5%
Critical value corresponding to 9 degrees of freedom and 5% significance level is 1.833.
Conclusion:
Reject the null hypothesis because the test statistic 2.21 is greater than the critical value 1.833.
His original goal to be successful is contained in the alternate hypothesis, therefore, he is meeting it.
Answer:
16-2n=-8+4n-12
16+8+12=4n
36/4=n
9=n
Step-by-step explanation:
9514 1404 393
Answer:
- 3n+6 (n = smallest)
- 3n (n = middle)
Step-by-step explanation:
The usual method for doing this is to let n represent the smallest one. Then the three integers are ...
n, n+2, and n+4
and their sum is ...
(n) +(n+2) +(n+4) = 3n+6 . . . . sum of 3 consecutive odd integers (n = smallest)
_____
Personally, for consecutive number problems, I prefer to let the variable represent the average value. If n is the average value of 3 consecutive odd integers, is is the middle integer. Of course, the sum will be 3 times the average:
(n-2) +(n) +(n+2) = 3n . . . . sum of 3 consecutive odd integers (n = middle one)
Step-by-step explanation:
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