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melomori [17]
3 years ago
8

Elizabeth continued to save for her car down payment.

Mathematics
2 answers:
Reil [10]3 years ago
6 0

ummmm it could be third one i guesss

wariber [46]3 years ago
6 0

Answer:

985

Step-by-step explanation:

they are asking what her balance was after her first deposit (A) so you only adding 65.00 to the original 920.00

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Add. Express your answer in standard form. (−3+5i)+(6+2i). Enter your answer in the box.
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You add/subtract complex numbers simply by adding/subtracting real parts and imaginary parts.

So, the real part of this sum is the sum of the real parts:

-3+6=3

And the imaginary part of this sum is the sum of the imaginary parts:

5i+2i=7i

So, you have

(-3+5i)+(6+2i) = 3+7i

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In a certain​ year, brand A of​ heart-rate watch cost ​$39.99 and brand B cost ​$59.99. A nonprofit community health organizatio
Oksi-84 [34.3K]

Answer:

Brand A = 21 heart-rate watches.

Brand B = 13 heart-rate watches.

Step-by-step explanation:

Let A be the number of Brand A heart watches and B be the number of Brand B heart watches.

We have been given that a nonprofit community health organization purchased 34 ​heart-rate watches for use at a wellness center.

We can represent this information in an equation as:

A+B=34...(1)

We have been given that in a certain​ year, brand A of​ heart-rate watch cost ​$39.99 and brand B cost ​$59.99 and the organization spent ​$1619.66 for the​ watches.

We can represent this information in an equation as:

39.99*A+59.99*B=1619.66...(2)

We will use substitution method to solve our system of equations.

From equation (1) we will get,

A=34-B

Substituting A=34-B in equation(2) we will get,

39.99*(34-B)+59.99*B=1619.66

1359.66-39.99*B+59.99*B=1619.66

-39.99*B+59.99*B=1619.66-1359.66

20*B=260

B=\frac{260}{20}

B=13

Therefore, the organisation purchased 13 heart-rate watches of brand B.

Now let us substitute B=13 in equation (1).

A+13=34

A+13-13=34-13

A=21

Therefore, the organisation purchased 21 heart-rate watches of brand A.

8 0
3 years ago
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